Answer:
Cat with 6 kg sitting on a 30 meter hill has greater potential energy.
Explanation:
gravitational potential energy (J) = mass (kg) × gravitational field × height (m)
<h3 /><h3><u>Note</u>:</h3>
gravitational field in Earth is 10 N/kg = <u>fixed unit</u>
<h3 /><h3><u>Given</u>:</h3>
1st Cat: 4 kg
2nd Cat: 6 kg
Both of their height is 30 meters.
<h3><u>Solve for g.p.e</u>:</h3>
1st cat = mgh = 4 × 10 × 30 = 1200 Joules
2nd cat = mgh = 6 × 10 × 30 = 1800 Joules
Answer: sea-level rise, extreme weather events, and drought, and water scarcity.
Explanation:
Answer:
a = 6.53 m/s^2
v = 11.5689 m/s
Explanation:
Given data:
engine power is 217 hp
70 % power reached to wheel
total mass ( car + driver) is 1530 kg
from the data given
2/3 rd of weight is over the wheel
w = 2/3rd mg
maximum force

we know that F = ma


the new power is 


solving for speed v

![v = 0.7 \frac{217 [\frac{746 w}{1 hp}]}{1500 \times 6.53}](https://tex.z-dn.net/?f=v%20%3D%200.7%20%5Cfrac%7B217%20%5B%5Cfrac%7B746%20w%7D%7B1%20hp%7D%5D%7D%7B1500%20%5Ctimes%206.53%7D)
v = 11.5689 m/s
A. Home birth
Hope this helps :)
Explanation:
let's assume that:
v1= 600ml=0,6l
T1=27°C= 300K
p1=700mmHG=93326Pa
T2=-20°C=253K
p2=500mmHg=66661
V2=?
p1V1/T1=p2V2/T2 => V2=p1V1T2/p2
V2= 93326*0,6*253/66661
V2=212,52l