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3 years ago

A behavior that is developed by observing others or being taught is

Physics

2 answers:

astra-53 [7]3 years ago

6 0

Answer:

Learned Behavior

Explanation:

Hatshy [7]3 years ago

5 0

B. Learned Behavior

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A sample contains 10g of radioactive isotope. How much radioactive isotope will remain in the sample after 3 half-lives?

Ainat [17]

Answer:

After 1 half-life (500 years), 500 g of the parent isotope will remain. After 2 half-lives (1000 years), 250 g of the parent isotope will remain. After 3 half-lives (1500 years), 125 g of the parent isotope will remain. After 4 half-lives (2000 years), 62.5 g of the parent isotope will remain.

Explanation:

3 0

3 years ago

The earth exerts the necessary centripetal force on an orbiting satellite to keep it moving in a circle at constant speed. Which

jenyasd209 [6]

Answer:

E) The centripetal force is always perpendicular to the velocity.

Explanation:

Due to gravity and inertia, the satellite follows a uniform circular motion. In this movement, the velocity is always tangent to the orbit and the centripetal force is directed towards the center. Therefore, there is no net acceleration in the same direction of velocity, which implies that it remains constant.

8 0

4 years ago

2. Imagine now that one tried to repeat the same measurement, but between the time that the warm water was measured and the time

Svetllana [295]

Answer:

The final temperature is 64.28°C.

Explanation:

Imagine now that one tried to repeat the same measurement, but between the time that the 400 cm³ of warm water was measured at 88°C and the time it was mixed with the 130 cm³ of cooler water at 15°C, the warmer water had lost 3060 cal to the environment. Calculate the final equilibrium temperature assuming no heat loss after mixing occurs.

Let the temperature of hot water before mixing is t

We need to calculate the temperature

Using formula of energy

$Q=mc\Delta t$

$Q=V\times\rho\times c\times(T_{2}-T_{1})$

Put the value into the formula

$3060=400\times1\times1\times(88-t)$

$3060=400\times88-400t$

$-t=\dfrac{3060-400\times88}{400}$

$t=80.35^{\circ}$

We need to calculate the final temperature

Using formula of temperature

$T_{f}=\dfrac{V_{w}T_{w}+V_{c}T_{c}}{V_{w}+V_{c}}$

Put the value into the formula

$T_{f}=\dfrac{400\times80.3+130\times15}{400+130}$

$T_{f}=64.28^{\circ}C$

Hence, The final temperature is 64.28°C.

5 0

4 years ago

A 2550 pound roller coaster starts from rest and is launched such that it crests a 119 ft high hill with a speed of 57 mph. The

Feliz [49]

To solve this problem we will apply the concepts related to energy conservation. For this purpose we will have that all the changes occurred in the energy change will be equivalent to the change in the potential and kinematic energies of the body. At the same time we will consider that the change in the final energy of the system will be reflected in the work of the system, therefore,

$\Delta E = KE+PE$