Question

A car has a constant acceleration of 5.6 m/s^2, it starts from test and reaches a speed of 280m/s, find the distance travelled by the car

Answer 1

Initial speed (u) = 0 m/s (Starts from rest)

Final speed (v) = 280 m/s

Acceleration (a) = 5.6 m/s²

By using equation of motion, we get:

$\bf \longrightarrow {v}^{2} = {u}^{2} + 2as \\ \\ \rm \longrightarrow {280}^{2} = {0}^{2} + 2 \times 5.6 \times s \\ \\ \rm \longrightarrow 78400 = 11.2s \\ \\ \rm \longrightarrow 11.2s = 78400 \\ \\ \rm \longrightarrow s = \dfrac{78400}{11.2} \\ \\ \rm \longrightarrow s = 7000 \: m \\ \\ \rm \longrightarrow s = 7 \: km$

$\therefore$ Distance travelled by the car (s) = 7 km