I think the answer is A: a line that is drawn horizontally around the earth and is parallel to the Prime Meridian
Hope this helps:)
Answer:
dispersion, dipole-dipole, and hydrogen bonding
Explanation:
The pictured compound is an amine. Amines have high boiling points. Amines have such high boiling points because they posses about three different kinds of intermolecular interactions, viz; hydrogen bonds, dispersion forces and dipole-dipole interactions.
The dipole interactions and hydrogen bonds arise from the fact that the N-H bond is polar. Also recall that a hydrogen bond is formed when hydrogen is bonded to an electronegative element. Hydrogen bonds lead to significant intermolecular association and high boiling points.
Hence the three kinds of intermolecular forces present in the pictured compound are; hydrogen bonding, dipole interactions and dispersion forces.
Answer:

Explanation:
We are asked to convert grams to moles. We will use the molar mass and dimensional analysis to perform this conversion.
<h3>1. Molar Mass</h3>
The molar mass is the mass of 1 mole of a substance. These values are found on the Periodic Table because they are equivalent to the atomic masses, but the units are grams per mole instead.
We are given a mass of sulfur dioxide (SO₂). Look up the molar masses of the individual elements.
- Sulfur (S): 32.07 g/mol
- Oxygen (O): 15.999 g/mol
Notice that the formula of the compound contains a subscript. The subscript after O means there are 2 moles of oxygen in 1 mole of sulfur dioxide. We must multiply oxygen's molar mass before adding sulfur's.
- O₂: 15.999 * 2 = 31.998 g/mol
- SO₂= 32.07 + 31.998 = 64.068 g/mol
<h3>
2. Convert Grams to Moles </h3>
Now we will use dimensional analysis to convert grams to moles. From the molar mass, we know there are 64.068 grams of sulfur dioxide per mole, so we can set up a ratio.

We are converting 151 grams to moles, so we multiply by this value.

Flip the ratio so the units of grams of sulfur dioxide cancel.




<h3>3. Round </h3>
The original measurement of grams (151) has 3 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place. The 6 in the thousandth place tells us to round the 5 in the hundredth up to a 6.

151 grams of sulfur dioxide is approximately <u>2.36 moles of sulfur dioxide.</u>
<u>Answer:</u> The frequency of the radiation is 33.9 THz
<u>Explanation:</u>
We are given:
Wave number of the radiation, 
Wave number is defined as the number of wavelengths per unit length.
Mathematically,

where,
= wave number = 
= wavelength of the radiation = ?
Putting values in above equation, we get:

Converting this into meters, we use the conversion factor:
1 m = 100 cm
So, 
- The relation between frequency and wavelength is given as:

where,
c = the speed of light = 
= frequency of the radiation = ?
Putting values in above equation, we get:


Converting this into tera Hertz, we use the conversion factor:

So, 
Hence, the frequency of the radiation is 33.9 THz
Answer:
8.9L is the volume of the gas that must be dissolved.
Explanation:
For a weak base, we can find [(CH₃)₃N] using the equation:
Kb = [OH⁻] [[(CH₃)₃NH⁺] / [(CH₃)₃N]
As [OH⁻] = [[(CH₃)₃NH⁺] and [OH⁻] = 10^-pOH = 3.16x10⁻³M:
6.3x10⁻⁵ = [3.16x10⁻³M][3.16x10⁻³M] / [(CH₃)₃N]
[(CH₃)₃N] = 0.1587M
As the volume is 2.5L, moles are:
2.5L * (0.1587mol / L) = 0.3968moles
Using:
PV = nRT
We can solve for volume of the gas as follows:
P = 1atm at STP; n = 0.3968moles; R = 0.082atmL/molK; T = 273.15K at STP
V = 0.3968mol*0.082atmL/molK*273.15K/1atm
V = 8.9L is the volume of the gas that must be dissolved.