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Alika [10]
3 years ago
15

Air is transferred from a 75 L tank where the pressure is 125 psi and the temperture is 288 k to a tire with a volume of 6.1 L a

nd a pressure of 25 psi. What is the new temperture.
Chemistry
1 answer:
aniked [119]3 years ago
4 0
<h3><u>Answer</u>;</h3>

 = 4.68 K

<h3><u>Explanation</u>;</h3>

According to the combined gas law;

P1V1/T1 = P2V2/T2

Given; P1 = 125 Psi

V1 = 75 L

T1 = 288 K

P2 = 25 PSI

V2 =6.1 L

Therefore;

T2 = P2V2T1/P1V1

    = (25×6.1 ×288)/(125×75)

    = 4.6848

    = 4.68 K

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3 years ago
Match each organ to its function. Tiles bone heart stomach lung Pairs pumps blood through the body Both provides structure for t
solniwko [45]
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7 0
3 years ago
Read 2 more answers
Magnesium oxide does not readily decompose into magnesium and oxygen. The reaction is shown below. MgO(s) + 601.7 kJ mc017-1.jpg
galben [10]
TEMPERATURE IS THE ANSWER 
5 0
3 years ago
Read 2 more answers
Consider the following Reaction.
jeyben [28]

Hey there!:

Molar mass of Mg(OH)2 = 58.33 g/mol


number of moles Mg(OH)2 :

moles of Mg(OH)2 = 30.6 / 58.33 =>  0.5246 moles

Molar mass of H3PO4 =  97.99 g/mol

number of moles H3PO4:

moles of Mg(OH)2 = 63.6 / 97.99 => 0.649 moles

Balanced chemical equation is:


3 Mg(OH)2 + 2 H3PO4 --->  Mg3(PO4)2 + 6 H2O


3 mol of Mg(OH)2 reacts with 2 mol of H3PO4  ,for 0.5246 moles of Mg(OH)2, 0.3498 moles of H3PO4 is required , but we have 0.649 moles of H3PO4, so, Mg(OH)2 is limiting reagent !

Now , we will use Mg(OH)2 in further calculation  .

Molar mass of Mg3(PO4)2 = 262.87 g/mol

According to balanced equation  :

mol of Mg3(PO4)2 formed = (1/3)* moles of Mg(OH)2


= (1/3)*0.5246


= 0.1749 moles of Mg3(PO4)2

use :

mass of Mg3(PO4)2 = number of mol * molar mass


= 0.1749 *  262.87

= 46 g of Mg3(PO4)2

Therefore:

% yield = actual mass * 100 / theoretical mass

% = 34.7 * 100 / 46

% = 3470 / 46

= 75.5%


Hope that helps!




3 0
3 years ago
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