Air is transferred from a 75 L tank where the pressure is 125 psi and the temperture is 288 k to a tire with a volume of 6.1 L a
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Answer:
We can have: Calcium, strontium, or barium
Explanation:
In this case, we have to remember the solubility rules for sulfate and the chloride
:
<u>Sulfate</u>
All sulfate salts are SOLUBLE-EXCEPT those also containing: Calcium, silver, mercury (I), strontium, barium or lead.(), which are NOT soluble.
<u>Chloride</u>
All chloride salts as SOLUBLE-EXCEPT those also containing: lead, silver, or mercury (I). (), which are NOT soluble.
If we the salt formed a precipitated with the sulfate anion, we will have as possibilities "Calcium, silver, mercury (I), strontium, barium or lead". If We dont have any precipitated with the Chloride anion we can discard "Silver, mercury (I), lead" and our possibilities are:
<u>"Calcium, strontium, or barium".</u>
I hope it helps!