Question

A small bar of gold whose density is 19.3 g/cm³, displaces 80 cm³ of water when dropped into a beaker. What's the mass of the bar of gold?

Answer 1

Answer:

$\boxed{\textbf{1.54 kg}}$

Explanation:

D = m/V

Data:

V = 80 cm³

D = 19.3 g/cm³

Calculation:

$\begin{array}{rcl}19.3 & = & \dfrac{m}{80}\\\\m & = & 19.3 \times 80\\& = & \text{1540 g}\\& = & \textbf{1.54 kg}\end{array}\\\text{The mass of the bar of gold is \boxed{\textbf{1.54 kg}} }$