Umm. Is this high school?.
4 friends x 2 ballons = 8 friends only ballons. 
8 + 1 = 9.
9 total
        
             
        
        
        
9514 1404 393
Answer:
   C
Step-by-step explanation:
The step shown indicates that y was eliminated from the equations. For choices A, B, D, this is done by adding the equations together (the y-coefficients are opposites). The result of doing that gives x-terms of 4x, 0x, and 0x, respectively. These x-terms do not match the one given: 2x.
For choice C, the y-term is eliminated by subtracting twice the second equation from the first. Doing that gives ...
   (4x +2y) -2(x +y) = (14) -2(3)
   4x +2y -2x -2y = 14 -6 . . . . eliminate parentheses
   2x = 8 . . . . . . . . . . . . . . collect terms
 
        
             
        
        
        
For (A.) Get a common denominator, 40/12 - 9/12 = 31/12 or (2 and 7/12)
For (B.) Get a common denominator, 24/15 - 10/15 = 14/15 (Simplified)
For (C.) Get a common denominator, 51/30 - 25/30 = 26/30 or (13/15)
For (D.) Get a common denominator, 14/6 - 9/6 = 5/6 (Simplified)
Hope this helps! 
PS: (Rate me brainliest?)
        
             
        
        
        
Let i = sqrt(-1) which is the conventional notation to set up an imaginary number
The idea is to break up the radicand, aka stuff under the square root, to simplify
sqrt(-8) = sqrt(-1*4*2)
sqrt(-8) = sqrt(-1)*sqrt(4)*sqrt(2)
sqrt(-8) = i*2*sqrt(2)
sqrt(-8) = 2i*sqrt(2)
<h3>Answer is choice A</h3>
 
        
             
        
        
        
Answer:
Step-by-step explanation:
You are to make 5 assemblies.
Each assembly requires the use of 1 Type A bolt.
To make the 5 assemblies, you need 5 Type A bolts.
The container of bolts has a total of 60 bolts.
The focus - Type A bolts - is 20 out of this 60.
The probability of obtaining a Type A bolt at all, is 20/60, which is = 1/3
(A) What is the probability of taking the exact number of Type A bolts you need for your 5 assemblies, if you randomly take 10 bolts from the container?
- The exact number of Type A bolts you need for the 5 assemblies is 5
1/3 × 5/10 =  5/30 =  1/6 =  0.167
(B) What is the probability of taking/having less than 5 Type A bolts out of the randomly selected 10 bolts? The solution is to sum up the following:
1/3 × 4/10 = 0.133
1/3 × 3/10 = 0.1
1/3 × 2/10 = 0.067
1/3 × 1/10 = 0.033
1/3 × 0/10 = 0
TOTAL = 0.333