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lana66690 [7]
3 years ago
12

What is an equation for this relationship? The table shows the total number of squares in each figure below.

Mathematics
1 answer:
antoniya [11.8K]3 years ago
4 0
I believe that it is D.
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10 raised to negative 3 in standard notation
larisa86 [58]
Standard notation simply means the normal way or writing numbers.
10^-3= 1/10^3
1/10^3=1/1000
1/1000=0.001
Final answer: 0.001
4 0
3 years ago
Question 2 of 10<br> Solve the equation x = gtr for r.
umka2103 [35]

Answer:

see attached.

Step-by-step explanation:

kindly see attached.

6 0
2 years ago
What is the value of x in the figure above? Assume ↔B and ↔C are parallel.
Deffense [45]

Answer:

x=4

Step-by-step explanation:

180-58=26x+18

122=26x+18

122-18=26x

104=26x

4=x

6 0
3 years ago
Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of
fomenos

Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>

Step-by-step explanation:

Given :  the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

Since, given the difference of the squares of the numbers is 5 that is (x^2-y^2)^2=5

And the product of the numbers is 6 that is xy=6

Using identity, we have,

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

Substitute, we have,

(x^2+y^2)^2=(5)^2+(2(6))^2

Simplify, we have,

(x^2+y^2)^2=25+144

(x^2+y^2)^2=169

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

5 0
2 years ago
Read 2 more answers
Write the missing number.<br> (a) 10 more than 23 is
Inessa05 [86]

Answer:

33

Step-by-step explanation:

10+23 according to my sense

3 0
3 years ago
Read 2 more answers
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