The answer is 2xy + 2856x^2y^2
Cymath.com works wonders my friend.
<span>c = w*45/13 + 60/13
I will be assuming that the equation will be linear since there are only 2 data points available. The form of the equation will be
c = aw + b
where
c = calories burned
a = some constant
w = weight
b = some other constant.
If you look at the equation, you'll notice that it looks like the equation for a line i slope intercept form. So first, let's calculate the slope of the desired equation.
a = (600-420)/(172-120) = 180/52 = 45/13 = 3.461538462
Now we have the equation
c = w*45/13 + b
Substitute the values for a known point, giving
420 = 120*45/13 + b
Now solve for b
420 = 120*45/13 + b
420 = 5400/13 + b
420 - 5400/13 = b
5460/13 - 5400/13 = b
60/13 = b
So now the equation is
c = w*45/13 + 60/13</span>
Answer:
The Answer is approximately: 20.22
Step-by-step explanation:
The distance formula is:
d = Sqrt ((x - x1)^2 + (y - y1)2)
The points are (5, -14), (-15, -17)
d = Sqrt ((5 - (-15))^2 + (-14 - (-17))^2)
d = Sqrt ((5 + 15)^2 + (-14 + 17)^2)
d = Sqrt (20^2 + 3^2)
d = Sqrt (400 + 9)
d = Sqrt (409) = 20.22
Answer:
36 %
Step-by-step explanation:
x% = x/100
27/75 = x/100
100 · 27/75 = 100 · x/100
2700/75 = x
36 = x
36%
Y=2(4)+8
y=8+8
y=16
Hope this helps :)