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3 years ago

Can you find the area for this?

Mathematics

2 answers:

Damm [24]3 years ago

7 0

Answer:

I think it's C) 18.5ft^2

it's just an educated guess though I haven't worked on area in a while

Kisachek [45]3 years ago

6 0

Answer:

$18.5ft^{2}$

Step-by-step explanation:

$A=(5*2.1)+(.5*2*5)+(.5*1.2*5)=18.5ft^{2}$

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I feel like something is wrong, is there?

Phoenix [80]

Answer:

# 4 (-5,2) should be placed one more place to the right

#5 (5,1) should be moved once up

Step-by-step explanation:

8 0

3 years ago

There are 416 students who are enrolled in an introductory geology course. if there are seven boys to every six girls, how many

Alenkinab [10]

$\text{Let the number of boys be x and number of girls be y.}\\
\\
\text{and there are total 416 students enrolled in the course. so we have}\\
\\
x+y=416 \ \ \ \ \ \ \ \ \ \ ......(i)\\
\\
\text{also given that there are seven boys to every six girls, that is}\\
\\
\frac{x}{y}=\frac{7}{6}$

$\Rightarrow 6x=7y\\
\\
\Rightarrow y=\frac{6x}{7}\\
\\
\text{substitute this value of y in (i), we get}\\
\\
x+\frac{6x}{7}=416\\
\\
\Rightarrow \frac{7x+6x}{7}=416\\
\\
\Rightarrow \frac{13x}{7}=416\\
\\
\Rightarrow x=\frac{416\times 7}{13}\\
\\
\Rightarrow x=224$

Hence the number of boys in the course are: 224

4 0

4 years ago

Using the trend line y = 8x + 8, for the data shown, complete the residual table.

Anit [1.1K]

Answer:

-1,0,2,-2,0 in that order

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A byte is used to measure a computer's memory. There are 2^30 bytes in a gigabyte. A computer has an 8 gigabyte memory. Which ex

aksik [14]

Answer:

8x2^30

Step-by-step explanation:

5 0

3 years ago

The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true

Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

Part A

$\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478$

Part B

$P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767$

Part C

$\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971$

6 0

2 years ago