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3 years ago

See the picture and Anwser This

Physics

1 answer:

lakkis [162]3 years ago

7 0

Answer:

20 m/s

Explanation:

Look at the time on the x-axis. Go up from 2 seconds until you reach a point. From that point go to the left and read from the y-axis.

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Organ pipe a, with both ends open, has a fundamental frequency of 340 hz. the third harmonic of organ pipe b, with one end open,

Sphinxa [80]

The fundamental frequency of the open pipe A
Length 'L₀' is, f₀ = U/2L₀ = 340 H₂
the speed of sound in air V= 343m/s
∴343/2L₀ = 340 → length L₀ = 343/2 ×340 = 0.5044 = 50.44
The third harmonic of closed pipe 'B' is
F3₀ = 3V/4LC
The second harmonic of open pipe 'A' is
f2₀ = 2V/2L₀
∴ 3V/4LC = 2V/2L →L₀ = 3L₀/4
⇒ The length of closed pipe B is
Lc = 37.83cm

7 0

3 years ago

Which statement would be a valid argument in favor of using nuclear power? There are few negative impacts from mining the fuel.

fgiga [73]

Okay so, lets use the process of elimination here.

<span>A)There are few negative impacts from mining the fuel.
B)Reactors are safe from natural disasters.
C)There are little to no waste products from fission.
D)Nuclear power does not contribute greenhouse gases.

First off, we know B cannot be correct, seeing as how reactors are fragile and are damaged easily by Japan's earthquakes. So we can eliminate B from the choices. We then can eliminate C, since fission creates high levels of nuclear waste, so that leaves us with just A, and D. We can then eliminate A since uranium is radioactive, there is always a chance for negative effects.

So, the correct answer is D</span>

6 0

3 years ago

Read 2 more answers

A 50 mL graduated cylinder contains 25.0 mL of water. A 42.5040 g piece of gold is placed in the graduated cylinder and the wate

Elenna [48]

Answer:

19320 kg/m³

Explanation:

density: This can be defined as the ratio of the mass of a body to its volume. The S.I unit of Density is kg/m³.

The formula of density is given as,

D = m/v ......................... Equation 1.

Where D = Density of the gold, m = mass of the gold, v = volume of the gold.

Note: From Archimedes's Principle, the piece of gold displace an amount of water that is equal to it's volume.

Amount of water displace = 27.2 - 25 = 2.2 mL.

Given: m = 42.504 g = 0.042504 kg, v = 2.2 mL = (2.2/10⁶) m³ = 0.0000022 m³

Substitute into equation 1

D = 0.042504/0.0000022

D = 19320 kg/m³

Hence the density of the piece of gold = 19320 kg/m³

5 0

4 years ago

Assuming that 70 percent of the Earth’s surface is covered with water at average depth of 0.95 mi, estimate the mass of the wate

Alla [95]

Answer:

The mass of the water on earth is $5.4537\times10^{20}\ kg$

Explanation:

Given that,

Average depth h= 0.95 mi

$h=0.95\times1.609$

$h =1.528\ km$

$h=1.528\times10^{3}\ m$

Radius of earth $r= 6.37\times10^{6}\ m$

Density = 1000 kg/m³

We need to calculate the area of surface

Using formula of area

$A =4\pi r^2$

Put the value into the formula

$A=4\pi\times(6.37\times10^{6})^2$

$A=5.099\times10^{14}\ m^2$

We need to calculate the volume of earth

$V = Area\times height$

Put the value into the formula

$V=5.099\times10^{14}\times1.528\times10^{3}$

$V=7.791\times10^{17}\ m^3$

Now, 70 % volume of the total volume

$V= 7.791\times10^{17}\times\dfrac{70}{100}$

$V=5.4537\times10^{17}\ m^3$

We need to calculate the mass of the water on earth

Using formula of density

$\rho = \dfrac{m}{V}$

$m = \rho\times V$

Put the value into the formula

$m=1000\times5.4537\times10^{17}$

$m =5.4537\times10^{20}\ kg$

Hence, The mass of the water on earth is $5.4537\times10^{20}\ kg$

8 0

4 years ago

Based on the graph of kinetic energy given (gray curve in the graphing window), sketch a graph of the baseball's gravitational p

chubhunter [2.5K]

1) Physical principles:

a) Total mechanical energy = kinetic energy + potential energy.

b) Total mechanical energy is conserved (neglecting external forces, like drag and friction)

2) Notation:

a) Total mechanical energy: ME.

b) Kinetic energy: KE

c) Gravitational potential energy: PE

∴ ME = KE + PE = constant

3) Solution:

a) Since, ME is conserved, it is constant and would be represented in the graph by a horizontal line.

b) At start (t = 0), the ball has only KE, so KE =ME = E and PE = 0

c) As the time goes, the ball gains altitude (PE increases) and loses speed (KE decreases).

d) PE increases from 0 to a maximum value. In the graph that happens at t = 2s.

At that point, KE = 0, and PE = ME.

That is the point of highest altitude and where the speed is zero.

d) From t = 2 seg, the ball starts to lose altitude, then the ball loses PE, and gains KE.

Just before reaching the ground, at t = 4s, the ball has the same initial KE and PE as at t = 0: KE = ME and PE = 0.

The PE may be sketched on the same graph along with the KE and the ME.

The graph is attached. The red line is the ME and the blue line is the PE.

Note that at any point in the graph PE + KE = ME.

5 0

4 years ago

Read 2 more answers