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Archy [21]
3 years ago
15

Organ pipe a, with both ends open, has a fundamental frequency of 340 hz. the third harmonic of organ pipe b, with one end open,

has the same frequency as the second harmonic of pipe
a. how long are (a) pipe a and (b) pipe b? (take the speed of sound to be 343 m/s.)
Physics
1 answer:
Sphinxa [80]3 years ago
7 0
The fundamental frequency of the open pipe A
Length 'L₀' is, f₀ = U/2L₀ = 340 H₂
the speed of sound in air V=  343m/s
∴343/2L₀ = 340 → length L₀ = 343/2 ×340 = 0.5044 = 50.44
The third harmonic of closed pipe 'B' is 
F3₀ = 3V/4LC
The second harmonic of open pipe 'A'  is
f2₀ = 2V/2L₀
∴ 3V/4LC = 2V/2L →L₀ = 3L₀/4
⇒ The length of closed pipe B is 
Lc = 37.83cm

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Follow these steps to solve this problem: Two identical loudspeakers, speaker 1 and speaker 2, are 2.0 m apart and are emitting
horsena [70]

Answer:

Explanation:

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Distance between first speaker and the given point = 4 m.

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Path difference = 4.472 - 4 = .4722 m.

Path difference / wave length = 0.4772 / 0.2 = 2.386

This is a fractional integer which is neither an odd nor an  even multiple of half wavelength. Hence this point of neither a perfect constructive nor a perfect destructive interference.

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4 years ago
How are light and sound waves affected by the different media they travel though?
seropon [69]
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Light waves do not require a medium to travel. This is how light can travel through space and we can see stars. Light waves travel at a much higher velocity as compared to sound waves. The velocity of light waves (through a vacuum) is 3 xx 10^8 m/s. In comparison, the velocity of sound waves (in air) is about 343 m/s. Different frequencies of light waves give rise to different colors. On the other hand, different frequencies of sound waves result in different pitches. Light waves and sound waves have very different frequencies from each other. Sound waves have low frequencies (20 to 20,000 Hz) as compared to light waves (~ 10^14 Hz).
8 0
4 years ago
What is the electric force acting between two charges of 0.0042 C and −0.0050 C that are 0.0030 m apart?
Black_prince [1.1K]

Answer:

A.−2.1 × 10^10 N

Explanation:

Using the formula;

E = k Q1Q2/d²

Where;

E is the electrical force  

k is the constant  

Q1, Q2 are the two charges  and

d is the distance between the two charges

Therefore;

E = (9 x 10^9) × (0.0042) × (-0.0050) / (0.0030)²  

 = -2.1 x 10^10 N

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6 0
4 years ago
Sam's job at the amusement park is to slow down and bring to a stop the boats in the log ride.
Mashcka [7]

The amount of work which Sam does need to stop the boat is 784Joule  if boat mass  is 800kg and boat drift in 1.4m/sec.

We know that according to work-energy theorem, change in kinetic energy of the body from one speed to another is equivalent to amount of work done by all forces acting on the body.

So, here we can see that final speed of boat is =0m/sec since Sam need to stop it.

Initial speed of boat is 1.4m/sec.

Also, we know that kinetic energy is given by the below formula:

Kinetic energy=(1/2)mv²

where m is the mass of the body

and v is the speed of the body

Now, from work energy theorem, we get

=>W=(1/2)mv^2_2 - (1/2)mv^2_1

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=>W= - 400× 1.4 × 1.4

=>W = -400×1.96

=>W= -784Joule

Here negative sign denotes work has to done against the original motion of boat.

Hence, amount of work needs to be done by Sam is 784Joule.

To know more about work,visit here:

brainly.com/question/18094932

#SPJ4

3 0
1 year ago
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