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ANEK [815]
3 years ago
6

(HELP QUICK!!) Air pressure is a result of _____

Physics
2 answers:
docker41 [41]3 years ago
7 0
I’m so sorry if it’s wrong, but I think it’s
A. Winds
katovenus [111]3 years ago
3 0

Answer:

A. Winds is the answer to the question

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I need help with this too. (im not good at science or math)
mr_godi [17]

Answer:

i belive 1 m/s

Explanation:

dividing displacement from time it should be 1 cuz 5/5 is 1

please tell me if right!

6 0
3 years ago
Read 2 more answers
Explain newton 2nd law ???<br><br>​
shusha [124]

Explanation:

Newton's second law simply says that the net force on an object is equal to the object's mass times its acceleration.

∑F = ma

For example, think of a game of tug-of-war, in which two teams pull on a rope in opposite directions.

If the forces are equal (balanced), then the net force is 0 N, so Newton's second law tells us that the rope's acceleration is 0 m/s².

If the forces are not equal (unbalanced), then the net force is not 0 N, and the rope will accelerate in the direction of the net force.

7 0
4 years ago
Projectiles Launched Horizontally Quiz
NikAS [45]

Answer:

3.0 seconds

Explanation:

The time of flight of a projectile (the time it takes to reach the ground) does not depend on the horizontal motion, but only on its vertical motion.

In fact, the time of flight is determined by the suvat equation:

s=ut+\frac{1}{2}gt^2

where

s is the vertical displacement

u is the initial vertical velocity (0, in case of these two projectiles)

g = 9.8 m/s^2 is the acceleration of gravity (assuming downward as positive direction)

t is the time of flight

Re-arranging the equation, we get

t=\sqrt{\frac{2s}{g}}

We see that this time depends only on s (the heigth of the cliff) and g: therefore, since the two projectiles are launched from the same height, they take the same time to reach the ground, 3.0 seconds.

7 0
3 years ago
A beam of 1.0 MHz ultrasound begins with an intensity of 1000 W/m². After traveling 12 cm through tissue with no significant ref
Ksenya-84 [330]

Answer:

Option C

Explanation:

Given:

- Depth of tissue d = 12 cm

- frequency of ultrasound f = 1 MHz

- Input Intensity I_i = 1000 W/m^2

- attenuation coefficient soft tissue a = 0.54

Find:

- Out-put intensity at the required depth

Solution

- The amount of attenuation in (dB) with the progression of depth is given by:

                                     Attenuation = a*f*d

                                     Attenuation = 0.54*12*1

                                     Attenuation = 6.48 dB

- The relation with attenuation and ratio of input and output intensity is given by:

                                     Attenuation = 10*log_10 (I_i / I_o)

                                     6.48 dB = 10*log_10 (I_i / I_o)

                                      I_i / I_o = 10^(0.648)

                                      I_o = 1000 / 10^(0.648)

                                      I_o = 225 W/m^2

- Hence the answer is option C:  I_o = 250 W/m^2  

4 0
4 years ago
In a(n) BLANK , the matter’s identity stays the same.
irina1246 [14]
Matter the same thing is gas or come dioxide
5 0
4 years ago
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