Initially, the spring stretches by 3 cm under a force of 15 N. From these data, we can find the value of the spring constant, given by Hook's law:

where F is the force applied, and

is the stretch of the spring with respect to its equilibrium position. Using the data, we find

Now a force of 30 N is applied to the same spring, with constant k=5.0 N/cm. Using again Hook's law, we can find the new stretch of the spring:
That's unaccelerated motion,
and constant velocity.
Answer:
Explanation:
For the first case , the expression for electrostatic force can be given by the following .
F = K x 8Q x 2Q / r² where k is a constant .
F = K 16 Q² / r²
When they touch , some charge is neutralized . Net charge remaining
= 8Q - 2 Q = 6 Q
Charge on each sphere = 6Q/2 = 3 Q .
Force between them
F₁ = k 3Q x 3 Q / r² = k 9 Q² / r²
F₁ / F = 9 / 16
F₁ = 9 F / 16 .
Answer:
Explanation:
The resistors in a unbalanced wheat stone bridge cannot be treated as a combination of series and parallel combination of resistors.
In case of balanced wheat stone bridge, the resistors can be treated as the combination of series and parallel combination.
Here, In the balanced wheat stone bridge
R1 and R2 be in series and Ra and Rx is series and then their combination is in parallel combination.