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3 years ago

Which function is equivalent to h(x)=10x^(2+9x-1)

Mathematics

2 answers:

Elina [12.6K]3 years ago

8 0

Answer:

h(x) = (10x - 1)(x + 1)

Step-by-step explanation:

Given

h(x) = 10x²+9x-1

Required

Get its equivalent

To do this, we simply factorize h(x)

We have that:

h(x) = 10x²+9x-1

Expand

h(x) = 10x² + 10x - x - 1

Factorize

h(x) = 10x(x + 1) -1(x + 1)

This gives:

h(x) = (10x - 1)(x + 1)

Hence, the equivalent of h(x) = 10x²+9x-1 is h(x) = (10x - 1)(x + 1)

saveliy_v [14]3 years ago

3 0

Answer: h(x) = (x+1) (10x-1)

Step-by-step explanation: I got it correct

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You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable preliminary estim

pogonyaev

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.025}{1.28})^2}=655.36$

And rounded up we have that n=656

Step-by-step explanation:

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 80% of confidence, our significance level would be given by $\alpha=1-0.80=0.20$ and $\alpha/2 =0.10$ . And the critical value would be given by:

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Solution to the problem

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

Since we don't have prior info for the proportion of interest we can use $\hat p=0.5$ as estimator. And on this case we have that $ME =\pm 0.025$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

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$n=\frac{0.5(1-0.5)}{(\frac{0.025}{1.28})^2}=655.36$

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3 years ago

Find the work done by gas?

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The work done by the gas when the gas expands will be 567.65 ft-lb.

<h3>What is the work done for an isothermal process?</h3>

The Pressure is inversely proportional to the volume.

Let the initial pressure and initial volume be P₁ and V₁, and the final volume be V₂.

Then the work done by the gas will be

WD = P₁ V₁ ln (V₂ / V₁)

A quantity of the gas with an initial volume of 2 cubic feet and an initial pressure of 700 pounds per square foot.

The gas expands to a volume of 3 cubic feet.

Then the work done by the gas will be

WD = 700 x 2 x ln (3/2)

WD = 1400 x 0.405

WD = 567.65 ft-lb

The work done by the gas when the gas expands will be 567.65 ft-lb.

More about the work done for isothermal process link is given below.

brainly.com/question/4218306

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