Note that we can also write equations for circles<span>, </span>ellipses, and hyperbolas<span> in terms of cos and sin, and other </span>trigonometric functions<span>; there are examples of these ...</span>
Let a₁ , a₂ , a₃ , a₄ ,... .be a given sequence.
The common ratio of this sequence is the following:
a₂/a₁ = a₃/a₂ = a₄/a₃ = r
Example: 5, 25, 125, 625, ...The common ration is:
25/5 = 125/25 = 625/125 = 5. So r=5 is the common ratio
The area of a square is simply the side length squared and we are given that the area is 125 so:
s^2=125
s=√125
s=5√5
Now using the area equation again, and adding 1 inch to s we have:
A=(s+1)^2, and using s found above we have:
A=(5√5+1)^2
A=125+10√5+1
A=126+10√5 in^2
A≈148.36 in^2 (to nearest hundredth of a square inch)
If I’m using substitution the answer is A
All you have to do is divide the left side of the ratio by 5 and the right side of the ratio by 7. The one that comes out even on both sides is the correct one.
