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maxonik [38]
3 years ago
11

PLEASE HELP

Mathematics
2 answers:
disa [49]3 years ago
7 0

the solution to the equation fraction 3 over 5 n minus fraction 4 over 5 equals fraction 1 over 5 n.

n = fraction 5 over 2

n = −1

n = fraction 5 over 3

n = 2

the last one is the answer.

alexira [117]3 years ago
4 0

9514 1404 393

Answer:

  n = 5/3

Step-by-step explanation:

Eliminate fractions, add 4, divide by the coefficient of n.

  \dfrac{3}{5} n-\dfrac{4}{5}=\dfrac{1}{5}\\\\3n-4=1 \qquad\text{multiply by 5}\\\\3n=5 \qquad\text{add4}\\\\\boxed{n=\dfrac{5}{3}} \qquad\text{divide by 3}

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Check My Work According to the National Association of Realtors, it took an average of three weeks to sell a home in 2017. Data
Salsk061 [2.6K]

Complete question :

According to the National Association of Realtors, it took an average of three weeks to sell a home in 2017. Suppose data for the sale of 39 randomly selected homes sold in Greene County, Ohio, in 2017 showed a sample mean of 3.6 weeks with a sample standard deviation of 2 weeks. Conduct a hypothesis test to determine whether the number of weeks until a house sold in Greene County differed from the national average in 2017. Useα = 0.05for the level of significance, and state your conclusion

Answer:

H0 : μ = 3

H1 : μ ≠ 3

Test statistic = 1.897

Pvalue = 0.0653

fail to reject the Null ; Hence, we conclude that their is no significant to accept the claim that number I weeks taken to sell a house differs.

Step-by-step explanation:

Given :

Sample size, n = 40

Sample mean, x = 3.6

Population mean, μ = 3

Standard deviation, s = 2

The hypothesis :

H0 : μ = 3

H1 : μ ≠ 3

The test statistic :

(xbar - μ) ÷ (s/√n)

(3.6 - 3) / (2/√40)

0.6 / 0.3162277

Test statistic = 1.897

Using T test, we can obtain the Pvalue from the Test statistic value obtained :

df = n - 1; 40 - 1 = 39

Pvalue(1.897, 39) = 0.0653

Decison region :

If Pvalue ≤ α ; Reject the null, if otherwise fail to reject the Null.

α = 0.05

Pvalue > α ; We fail to reject the Null ; Hence, we conclude that their is no significant to accept the claim that number I weeks taken to sell a house differs.

7 0
3 years ago
Evaluate the expression shown below and write your answer as a fraction in simplest form.
Ierofanga [76]

Answer:

72 / 5

Step-by-step explanation:

( 12 / 5 ) + ( 6 / 5 )

= ( 12 + 6 ) / 5

= 18 / 5

[ ( 12 / 5 ) + ( 6 / 5 ) ] / ( 1 / 4 )

= ( 18 / 5 ) / ( 1 / 4 )

= ( 18 x 4 ) / 5

= 72 / 5

8 0
2 years ago
Nestor works at a garden center where he posts plants. It takes him 2 1/2 hours to pot 15 plants. How many plants can Nestor pot
guapka [62]

Answer:

Nestor can pot 6 plants in 1 hour.

Step-by-step explanation:

first lets convert 2 1/2 hours in mixed fraction form for better calculation

2 1/2 hours = (2*2 + 1)/2 = 5/2 hours

no of plants pot in  5/2 hours = 15

to find no. of plants pot in 1 hours lets

divide both side by 5/2

no of plants pot in  5/2/(5/2)  hours = 15/(5/2) = 15*2/5 = 6

no. of plants pot in 1 hour = 6

Thus, Nestor can pot 6 plants in 1 hour.

6 0
3 years ago
What is 8.4 x 10^-6 in standard notation ?
FinnZ [79.3K]
Is the answer 0.0000084
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Read 2 more answers
A physical education teacher wanted to test whether her county’s students are falling below the national proportion. It is known
Ipatiy [6.2K]

Answer:

(a) The population parameter is students who ran the mile in less than 10 minutes.

(b) The hypothesis being tested is:

H0: p = 0.70

Ha: p < 0.70

(c) The significance level is 0.05.

(d) In order to conduct a one-sample proportion z-test, the following conditions should be met:

The data are a simple random sample from the population of interest.

The population is at least 10 times as large as the sample.

n⋅p ≥ 10 and n⋅(1−p) ≥ 10, where n is the sample size and p is the true population proportion.

n⋅p = 756 * 0.70 ≥ 10

n⋅(1−p) = 756 * (1 - 0.70) ≥ 10

All the conditions are met.

(e) p = 504/756 = 0.67

The test statistic, z = (p - p)/√p(1-p)/n = (0.67 - 0.70)/√0.70(1-0.70)/756 = -2.00

(f) The p-value is 0.0228.

(g) Since the p-value (0.0228) is less than the significance level (0.05), we can reject the null hypothesis.

(h) Therefore, we can conclude that less than 70% of students run one mile in less than 10 minutes.

Step-by-step explanation:

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