Answer: c. –1 and .1587
Step-by-step explanation:
As per given , we have
Null hypothesis : 
Alternative hypothesis : 
Since Alternative hypothesis is left-tailed ,so the test must be a left tailed test .
Z -Test statistic for proportion = 
, where p= population proportion
= sample proportions
n= Sample size.
Let x be the number of successes.
For n= 40 and x= 11
Then , 



By using z-table ,
P-value for left-tailed test = P(z<-1)= 1-P(z<1) [∵ P(Z<-z)= 1-P(Z<z) ]
= 1-0.8413
=0.1587
Hence, the -score and P-value are <u>–1 and 0.1587</u> .
So the correct option is c. –1 and .1587
Answer:
The answer all together would be 5 minus n.
Step-by-step explanation:
a negative and a positive equals a positive so -1/2 + 1 1/2 would equal 2 and 2 + 3 equals 5. Then, the remaining numbers are 5 and n. The final answer is 5 minus n because n is unknown.
The answer is B because 3600 divided by 40 is ninety
Answer:
We are 95% confident that the true proportion of TV audience is between 65.15% and 65.85%
Step-by-step explanation:
-From the given information,
.
-We calculate the confidence interval using this value at 95% confidence level:
![CI=\hat p\pm z \sqrt{\frac{\hat p(1-\hat p)}{n}}\\\\\\=0.65\pm 1.96\times \sqrt{\frac{0.65\times 0.35}{12000}}\\\\\\=0.65\pm 0.0085\\\\\\=[0.6415,0.6585]](https://tex.z-dn.net/?f=CI%3D%5Chat%20p%5Cpm%20z%20%5Csqrt%7B%5Cfrac%7B%5Chat%20p%281-%5Chat%20p%29%7D%7Bn%7D%7D%5C%5C%5C%5C%5C%5C%3D0.65%5Cpm%201.96%5Ctimes%20%5Csqrt%7B%5Cfrac%7B0.65%5Ctimes%200.35%7D%7B12000%7D%7D%5C%5C%5C%5C%5C%5C%3D0.65%5Cpm%200.0085%5C%5C%5C%5C%5C%5C%3D%5B0.6415%2C0.6585%5D)
So, the 95% confidence interval is (0.6515,0.6585).
Hence, we are 95% confident that the true proportion of TV audience is between 65.15% and 65.85%.
Answer:
19968
Step-by-step explanation:
Use the distributive property-
To “distribute” means to divide something or give a share or part of something. According to the distributive property, multiplying the sum of two or more addends by a number will give the same result as multiplying each addend individually by the number and then adding the products together.