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leonid [27]
2 years ago
8

An albatross is a large bird that can fly 400 kilometers in 8 hours at a constant speed. Using d for distance in kilometers and

t for number of hours, an equation that represents this situation is d=50t. The equation tells us: to find the distance (d), multiply the time (t) by 50.
What are two constants of proportionality for the relationship between distance in kilometers and number of hours?

What is the relationship between these two values?

Write another equation that relates d and t in this context. HINT: Think about what you do to find t. This equation will begin with t= _
Mathematics
2 answers:
finlep [7]2 years ago
7 0

Answer:

explain it better plz

Step-by-step explanation:

Alika [10]2 years ago
5 0

Answer:

2500

Step-by-step explanation:

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If there are 16 ounces in one pound than how many ounces are there in a half pound?
miskamm [114]

Answer:

there are 8 ounces in a half pound

Step-by-step explanation:

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3 years ago
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Find the x-intercept and y-intercept of the line.<br> 6x + 3y = - 18<br> I NEED HELP ASP
ser-zykov [4K]
X-intercept = -3
y- intercept = -6
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3 years ago
Given the quadratic function
hjlf

The vertex is (-4,-3)

The axis of symmetry is x=-4

and the transformations are:

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3 years ago
Plz help me and plz show work 1.
gulaghasi [49]

Answer:

400 800 1200 1600 2000 is anwser

3 0
3 years ago
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Two points in the Cartesian plane are A(2.00 m, −4.00 m) and B(−3.00 m, 3.00 m). Find the distance between them and their polar
Brrunno [24]

The distance between the two points is d=8.6m

The polar coordinate of A is \left(4.47,296.57\right)

The polar coordinate of B is \left(4.24,135\right)

Explanation:

The two points are A(2,-4) and B(-3,3)

The distance between two points is given by,

d=\sqrt{(2+3)^{2}+(-4-3)^{2}}\\d=\sqrt{(5)^{2}+(-7)^{2}}\\d=\sqrt{25+49}\\d=8.6

Thus, the distance between the two points is d=8.6m

The polar coordinates of A can be written as (Distance, tan^{-1} \frac{y}{x} )

Distance = \sqrt{x^{2} +y^{2} }

Substituting A(2,-4), we get,

Distance = \sqrt{2^{2} +(-4)^{2} }=\sqrt{4+16 }=4.47

tan^{-1} \frac{y}{x} =tan^{-1} \frac{-4}{2}=-63.43

To make the angle positive, let us add 360,

\theta=360-63.43=296.57

The polar coordinate of A is \left(4.47,296.57\right)

Similarly, The polar coordinate of B can be written as (Distance, tan^{-1} \frac{y}{x} )

Distance = \sqrt{x^{2} +y^{2} }

Substituting B(-3,3), we get,

Distance = \sqrt{(3)^{2}+(3)^{2}}=4.24

tan^{-1} \frac{y}{x} =tan^{-1} \frac{3}{-3}=-45

To make the angle positive, let us add 360,

\theta=180-45=135^{\circ}

The polar coordinate of B is \left(4.24,135\right)

5 0
3 years ago
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