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alexira [117]
3 years ago
8

The hormone thyroxine is secreted by the thyroid gland and has the formula: C15H17NO4I4. How many milligrams of Iodine can be ex

tracted from 15.0 grams of thryoxine?
Chemistry
2 answers:
yan [13]3 years ago
7 0

Answer : The mass of iodine extracted can be 9796.7 mg

Explanation : Given,

Mass of thryoxine = 15.0 g

Molar mass of thryoxine = 776.86 g/mole

The molecular formula of thryoxine is, C_{15}H_{11}NO_4I_4

In C_{15}H_{11}NO_4I_4 compound, there are 15 moles of carbon, 11 moles of hydrogen, 1 mole of nitrogen, 4 moles of oxygen and 4 moles of iodine.

First we have to determine the moles of thryoxine.

\text{Moles of thryoxine}=\frac{\text{Mass of thryoxine}}{\text{Molar mass of thryoxine}}=\frac{15.0g}{776.86g/mole}=0.0193moles

Now we have to determine the moles of iodine.

As, 1 mole of thryoxine has 4 moles of iodine

So, 0.0193 mole of thryoxine has 4\times 0.0193=0.0772 moles of iodine

Now we have to determine the mass of iodine.

\text{Mass of iodine}=\text{Moles of iodine}\times \text{Molar mass of iodine}

\text{Mass of iodine}=(0.0772mole)\times (126.9g/mole)=9.7967g=9796.7mg

conversion used : (1 g = 1000 mg)

Therefore, the mass of iodine extracted can be 9796.7 mg

Ede4ka [16]3 years ago
6 0
I'm pretty sure it's 9726 milligrams of iodine. Hope this helps.
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You want to make 500 ml of a 1 N solution of sulfuric acid (H2SO4, MW: 98.1). How many grams of sulfuric acid do you need?
umka21 [38]

Answer:

24.525 g of sulfuric acid.

Explanation:

Hello,

Normality (units of eq/L) is defined as:

N=\frac{eq_{solute}}{V_{solution}}

Since the sulfuric acid is the solute, and we already have the volume of the solution (500 mL) but we need it in liters (0.5 L, just divide into 1000), the equivalent grams of solute are given by:

eq_{solute}=N*V_{solution}=1\frac{eq}{L}*0.5L=0.5 eq

Now, since the sulfuric acid is diprotic (2 hydrogen atoms in its formula) 1 mole of sulfuric acid has 2 equivalent grams of sulfuric acid, so the mole-mass relationship is developed to find its required mass as follows:

m_{H_2SO_4}=0.5eqH_2SO_4(\frac{1molH_2SO_4}{2 eqH_2SO_4}) (\frac{98.1 g H_2SO_4}{1 mol H_2SO_4} )\\m_{H_2SO_4}=24.525 g H_2SO_4

Best regards.

4 0
3 years ago
What does contact forces and non-contact forces mean?
Dmitrij [34]
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8 0
3 years ago
What is the empirical formula of a compound that is 24.42 % calcium, 17.07 % nitrogen, and 58.5% oxygen?
REY [17]

Answer:

CaN_{2} O_{6}

Explanation:

When calculating an empirical formula from percentages, assume you have a 100g sample. This allows you to convert the percentages directly to grams, because X % of 100g is X grams.

So:

24.42 % = 24.42 g Ca, 17.07% = 17.07g N, 58.5% = 58.5g O

The next step is to divide each mass by their molar mass to convert your grams to moles.

24.42/40.08 = 0.6092 mol

17.07/14.01 = 1.218 mol

58.85/15.99 = 3.680 mol

Then you will divide all of your mol values by the SMALLEST number of moles. This gives you whole numbers that are the mole ratio (subcripts) of the empircal formula.

0.6092 mol/0.6092 mol = 1

1.218 mol/0.6092 mol = 2

3.680 mol/0.6092 mol = 6

So the empirical formula is CaN_{2} O_{6}

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