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alexira [117]
3 years ago
8

The hormone thyroxine is secreted by the thyroid gland and has the formula: C15H17NO4I4. How many milligrams of Iodine can be ex

tracted from 15.0 grams of thryoxine?
Chemistry
2 answers:
yan [13]3 years ago
7 0

Answer : The mass of iodine extracted can be 9796.7 mg

Explanation : Given,

Mass of thryoxine = 15.0 g

Molar mass of thryoxine = 776.86 g/mole

The molecular formula of thryoxine is, C_{15}H_{11}NO_4I_4

In C_{15}H_{11}NO_4I_4 compound, there are 15 moles of carbon, 11 moles of hydrogen, 1 mole of nitrogen, 4 moles of oxygen and 4 moles of iodine.

First we have to determine the moles of thryoxine.

\text{Moles of thryoxine}=\frac{\text{Mass of thryoxine}}{\text{Molar mass of thryoxine}}=\frac{15.0g}{776.86g/mole}=0.0193moles

Now we have to determine the moles of iodine.

As, 1 mole of thryoxine has 4 moles of iodine

So, 0.0193 mole of thryoxine has 4\times 0.0193=0.0772 moles of iodine

Now we have to determine the mass of iodine.

\text{Mass of iodine}=\text{Moles of iodine}\times \text{Molar mass of iodine}

\text{Mass of iodine}=(0.0772mole)\times (126.9g/mole)=9.7967g=9796.7mg

conversion used : (1 g = 1000 mg)

Therefore, the mass of iodine extracted can be 9796.7 mg

Ede4ka [16]3 years ago
6 0
I'm pretty sure it's 9726 milligrams of iodine. Hope this helps.
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3 years ago
Calculate the number of moles of solute in 16.55 mL of 0.1475 M M2Cr3O7
aliina [53]

Number of moles of solute in 16.55 mL of 0.1475 M M2Cr3O7 is 0.00244 moles.

<u>Explanation:</u>

The properties and behavior of many solutions depend not only on the nature of the solute and solvent but also on the concentration of the solute in the solution. Molarity (M) is the concentration of a solution expressed as the number of moles of solute per liter of solution:

Molarity = \frac{moles-solute}{lites-solution},

Here , litres-solution = \frac{16.55}{1000} l = 0.01655l.

⇒ Molarity = \frac{moles-solute}{lites-solution}

⇒ 0.1475 = \frac{moles-solute}{0.01655}

⇒ moles-solute = 0.01655(0.1475)

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6 0
3 years ago
What is the molarity of a solution prepared by diluting 250 mL of a 40% H2SO4 solution to 1 Liter? The density of the stock solu
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Answer:

1.195 M.

Explanation:

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<em>M = (10Pd)/(molar mass).</em>

Where, M is the molarity of H₂SO₄.

P is the percent of H₂SO₄ (P = 40%).

d is the density of H₂SO₄ (d = 1.17 g/mL).

molar mass of H₂SO₄ = 98 g/mol.

∴ M of stock H₂SO₄ = (10Pd)/(molar mass) = (10)(40%)(1.17 g/mL) / (98 g/mol) = 4.78 M.

  • We have the role that the no. of millimoles of a solution before dilution is equal to the no. of millimoles after dilution.

<em>∴ (MV) before dilution = (MV) after dilution</em>

M before dilution = 4.78 M, V before dilution = 250 mL.

M after dilution = ??? M, V after dilution = 1.0 L = 1000 mL.

∴ M after dilution = (MV) before dilution/(V after dilution) = (4.78 M)(250 mL)/(1000 mL) = 1.195 M.

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