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2 years ago

What is the area of this square the height is 4 in the width is 4

Mathematics

1 answer:

puteri [66]2 years ago

3 0

Answer;

Step-by-step explanation:

eee 4*4*4=64

sorry if im wrong, since it's a square than all the sides are the same, if it is a 3d CUBE then the area is 64 but if you're talking about a 2d square then its 16

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Rita gets paid $16 per hour for the first 8 hours she works each day. She earns 1 1 2 times her hourly pay rate for time she wor

omeli [17]

<h3>The total money earned by Rita on Monday = $158</h3>

Step-by-step explanation:

The rate by which Rita is paid first 8 hours = $16

The next per hour rate after 8 hours = $1\frac{1}{2} = 1.5$ times the usual rate.

Now, 1.5 times $16 = 1.5 x 1 6 = $24

So, for each hour worked after 8th hour, Rita is paid $24 per hour.

Now, the intervals she has worked are:

(a) from 8:15 to 12: 45 pm

So, the number of hours worked = 45 minutes + 45 minutes + 3 hours

= 4 hours 30 minutes .... (1) (as 60 minutes = 1 hour)

(b) break of 45 minutes after 12: 45 = 12: 45 + 45 minutes

= 12 hour 90 minutes = 1 : 30 P M

So, she started working at 1: 30 and worked till 6: 15

So, the number of hours worked = 30 minutes + 15 minutes +4 hours

= 4 hours 45 minutes .... (2)

So, by adding (1) and (2) the total hours worked by Rita

= 4 hours 30 minutes + 4 hours 45 minutes

= 8 hours 75 minutes = 9 hours 15 minutes

9 hours 15 minutes = ( 8 + 1 .25 ) ( 15 minutes = 0.25 of an hour)

So, the payment is ( 8 x (16) + 1.25 (24) )

= 128 + 30 = 158

Hence, the total money earned by Rita = $158

6 0

3 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

marusya05 [52]

Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

$n= 955$ represent the sampel size slected

$x = 812$ number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

The confidence interval for the proportion would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the significance is $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution and we got.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

8 0

3 years ago

Is 11/15 less than 1/2

Art [367]

No because if you convert them into a percentage, you get 11/15 as 73.3% and 1/2 is 50%. Hope this helps

6 0

3 years ago

Read 2 more answers

A random sample of 4"4 fields" of barley has a mean yield of "49.6"49.6 bushels per acre and standard deviation of 7.997.99 bush

ExtremeBDS [4]

Answer:

The critical value that should be used in constructing the interval is T = 5.8408.

The 99% confidence interval for the true mean yield is between 2.943 bushels per acre and 96.268 bushels per acre.

Step-by-step explanation:

We have the standard deviation of the sample, so we use the students t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 4 - 1 = 3

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 3 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.99}{2} = 0.995$ . So we have T = 5.8408. This is the critical value.

The margin of error is:

M = T*s = 5.8408*7.99 = 46.668 bushels per acre

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 49.6 - 46.668 = 2.943 bushels per acre.

The upper end of the interval is the sample mean added to M. So it is 49.6 + 46.668 = 96.268 bushels per acre.

The 99% confidence interval for the true mean yield is between 2.943 bushels per acre and 96.268 bushels per acre.

8 0

3 years ago

What is 66×94÷996-9 Please answer quicly

zhenek [66]

Answer:

I am pretty sure it's −2.7710843373

8 0

3 years ago

Read 2 more answers