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Rudik [331]
3 years ago
5

Write out the balanced chemical equation and the net ionic equation for the reaction between hydrochloric acid and sodium hydrox

ide, using smallest whole number stoichiometric coefficients.
Chemistry
1 answer:
polet [3.4K]3 years ago
7 0

Answer:

HCl(aq) + NaOH(aq) ⇒ NaCl(aq) + H₂O(l)

H⁺(aq) + OH⁻ ⇒ H₂O(l)

Explanation:

Let's consider the balanced chemical equation (molecular equation) for the reaction between hydrochloric acid and sodium hydroxide. This is a neutralization reaction.

HCl(aq) + NaOH(aq) ⇒ NaCl(aq) + H₂O(l)

The complete ionic equation includes all the ions and the molecular species.

H⁺(aq) + Cl⁻(aq) + Na⁺(aq) + OH⁻ ⇒ Na⁺(aq) + Cl⁻(aq) + H₂O(l)

The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and the molecular species.

H⁺(aq) + OH⁻ ⇒ H₂O(l)

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3 years ago
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If a solution containing 0.10 M Cl-, Br-, I-, and LaTeX: CrO_4^2-C r O 4 2 − is treated with Ag+, in what order will the anions
Musya8 [376]

Answer:

AgI \longrightarrow AgBr \longrightarrow Ag_2CrO_4 \longrightarrow AgCl

Explanation:

The first thing to have in mind is that the Ksp (constant of solubility) gives you an idea of how much soluble a salt is.  <u>If the concentration of ions of that salt exceeds the kps, the salt will precipitate</u>.

The Kps of all these salts are very small compared to the 0.1 M concentration of the anions so all of them will precipitate.

The smaller the constant, the faster the salt precipitates

Having that concept in mind, the order of precipitation from first to last would be:

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6 0
3 years ago
Show how to carry out the transformation of benzene to chlorobenzene by going through a diazonium intermediate.
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5 0
3 years ago
BE FIRST TO ANSWER FOR SUM GOOD!!!!!:D
kipiarov [429]
Answer is B can you like btw??
3 0
3 years ago
Explain how you would make 500ml of a 0.100 m naoh solution
icang [17]
Molar mass NaOH =23+16+1=40 g/mol
<span> 0.100 M= 0.100 mol/L
</span>500 ml=0.500 L
0.500L*0.100 mol/L=0.0500 mol NaOH we need to prepare 500 ml solution
0.0500 mol NaOH*40g/1mol=2 g NaOH we need to prepare 500 ml solution
we need  2 g NaOH, dissolve it in small amount of water, and dilute it with water up to 500 mL
3 0
3 years ago
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