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ad-work [718]
3 years ago
10

An occluded front moves over farmland that has been experiencing drought conditions.

Chemistry
2 answers:
photoshop1234 [79]3 years ago
7 0
Drought means a shortage of water. The answer is either c or d. Since there is no water/rain during a drought those factors can instantly tell us that it’s not a or b. So it is c or d
cupoosta [38]3 years ago
6 0
Should be B. An extended period of rain
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How many elements and atoms are in marble
DochEvi [55]

Answer:

Explanation:

Scientists know that there are 6x1023 molecules in a mole - so we have about 0.5x1023 molecules in our marble…and since every silicon dioxide molecule has one atom of silicon and two of oxygen, we have a grand total of 1.5x1023 atoms. That's 150,000,000,000,000,000,000,000 atoms

7 0
3 years ago
What compound does hydrogen form?​
Oxana [17]
It forms covalent compounds
6 0
3 years ago
Read 2 more answers
How will overshooting the endpoint in the titration affect your final result?
pickupchik [31]
The end result will be inaccurate as the concentration of the acid or base being calculated will be more concentrated than it actually is due to the endpoint being surpassed
5 0
3 years ago
What is the energy of a photon with a frequency of 9.50 x 1013 Hz?
Taya2010 [7]

Answer:

\huge{6.295 \times  {10}^{ - 20}  \: J}

Explanation:

The energy of the photon can be found by using the formula

E = hf

where

E is the energy

f is the frequency

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question we have

E = 6.626 × 10-³⁴ × 9.5 × 10¹³

We have the final answer as

6.295 \times  {10}^{  - 20}  \: J

Hope this helps you

3 0
2 years ago
I’ll mark as brainliest
zysi [14]

First, let's count mole of 10 g Calcium Carbonate

mole = Mass / Molecular Mass

Calcium Carbonate = CaCO₃

Molecular Mass = Ar Ca + Ar C + (3 x Ar O)

Molecular Mass = 40 + 12 + (3 x 16)

Molecular Mass = 100

next

Mole of CaCO₃ = 10 gram / 100

Mole of CaCO₃ = 0,1 mol

then equal the reaction equation first

 CaCO₃ + 2 HCl  ==>  CaCl₂ +  CO₂  +  H₂O     (Equal)

To count the mass of carbon dioxide that produced we must know the mole of CO₂ first

we can count by coefficient comparison

mole CO₂ = \frac{coefficient \ of \ CO_2}{coefficient \ of \ CaCO_3}  x mole CaCO₃

mole  CO₂ =  (1/1)  x 0,1 mole

mole  CO₂ = 0,1 mole

so

Mass of  CO₂ = mole  CO₂ x  Molecular Mass of  CO₂

Mass of  CO₂ = 0,1 mole x (12 + (2 x 16))

Mass of  CO₂ = 0,1 mole x 44

Mass of  CO₂ = 4,4 g

so, mass of carbon dioxide that's produced by 10 g of calcium carbonate on reaction with chloride acid is 4,4 g.

6 0
3 years ago
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