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Alika [10]
3 years ago
7

Why wouldn't two cations form a covalent bond?

Chemistry
1 answer:
Allushta [10]3 years ago
4 0

Answer:

Covalent bonding is the sharing of electrons between atoms. In addition, the ionization energy of the atom is too large and the electron affinity of the atom is too small for ionic bonding to occur.

For example: carbon does not form ionic bonds because it has 4 valence electrons, half of an octet.

Explanation:

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What are some properties that a question must have in order to be a scientific question​
GarryVolchara [31]

Answer:

https://www.enotes.com/homework-help/what-scientific-question-520157

Explanation:

cuz it is (copy and paste)

6 0
4 years ago
What is the acceleration of a car that goes from 50km/hour to 90 km/hour in 5 seconds?
BartSMP [9]

Answer:

the acceleration i think is 8

Explanation:

50+5x8

6 0
3 years ago
What is the difference between primary scale and extension scale?
elena-14-01-66 [18.8K]

Answer:

8txirzrz8rzrirzriz£=,£=,,-8/-9/-¥/

Explanation:

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8 0
3 years ago
How many atoms are present in 0.529 moles of Li?
nirvana33 [79]

Answer:

<h2>3.18 × 10²³ atoms</h2>

Explanation:

The number of atoms can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 0.529 × 6.02 × 10²³

We have the final answer as

<h3>3.18 × 10²³ atoms</h3>

Hope this helps you

6 0
3 years ago
How much energy is required when a 142.1 gram sample of aluminum goes from 25.5°C to 46°C? (the specific heat of aluminum is 0.9
vfiekz [6]

Answer:

2621.75 j heat is required to increase the temperature 25.5°C to 46°C.

Explanation:

Given data:

Mass of sample = 142.1 g

Initial temperature = 25.5°C

Final temperature = 46°C

Specific heat capacity of Al = 0.90 J/g.°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 46°C - 25.5°C

ΔT = 20.5°C

Q = 142.1 × 0.90 J/g.°C × 20.5°C

Q = 2621.75 j

Thus,  2621.75 j heat is required to increase the temperature 25.5°C to 46°C.

4 0
3 years ago
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