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ANTONII [103]
3 years ago
9

Supppose a rectangle will undergo a rotation about the origin of a coordinate plane and a translation of 6 units down. Which of

these is a true statement
Mathematics
1 answer:
Nitella [24]3 years ago
8 0

Options:

The resulting rectangle will be congruent to the original rectangle regardless of the order of the rotation and the translation.

The resulting rectangle will be congruent to the original rectangle only if the rotation occurs before the translation.

The resulting rectangle will be congruent to the original rectangle only if the translation occurs before the rotation.

The resulting rectangle will not be congruent to the original rectangle regardless of the order of the rotation and the translation.

Answer:

The resulting rectangle will be congruent to the original rectangle regardless of the order of the rotation and the translation.

Step-by-step explanation:

<em>See attachment for options</em>

Given

Shape: Rectangle

Transformation

- Rotation

- Translation 6 units down

Required

True statement about the transformation

From the options, we understand that we are to answer the question based on whether or not the image of the transformation will equal the original.

The given transformations are rigid transformations and as such, they do not in any way change the measure of the length and/or angle of the new image, after transformation

So, irrespective of which transformation comes first, both shapes will be congruent.

Hence: (a) is true

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Perpendicular to the line 4x - 6y + 7 = 0 , passing through (3, 4) .
PilotLPTM [1.2K]

Answer:

The equation of line perpendicular to given line passing through (3,4) is:

y = -\frac{3}{2}x+\frac{17}{2}

Step-by-step explanation:

Given equation of line is:

4x - 6y + 7 = 0

Given equation is in standard form. It has to be converted into slope-intercept form to extract slope from the equation.

So,

4x+7 = 6y\\6y=4x+7\\\frac{6y}{6} = \frac{4x+7}{6}\\y = \frac{4}{6}x+\frac{7}{6}\\y=\frac{2}{3}x+\frac{7}{6}

The standard form of slope-intercept form of equation is:

y=mx+b

Here, the co-efficient of x is the slope of the line.

So the slope of given line is: 2/3

m = 2/3

The product of slopes of two perpendicular lines is -1

Let m1 be the slope of line perpendicular to given line

Then

m.m_1 = -1\\\frac{2}{3} . m_1 = -1\\m_1 = -1*\frac{3}{2}\\m_1 = -\frac{3}{2}

The equation of perpendicular will be:

y = m_1x+b

Putting the value of slope

y = -\frac{3}{2}x+b

To find the value of b, putting (3,4) in the equation

4 = -\frac{3}{2}(3)+b\\4 = -\frac{9}{2}+b\\b = 4+\frac{9}{2}\\b= \frac{8+9}{2}\\b=\frac{17}{2}

So the equation of line perpendicular to given line passing through (3,4) is:

y = -\frac{3}{2}x+\frac{17}{2}

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