2 years ago

PLEASE HELP :((

Mathematics

1 answer:

Mazyrski [523]2 years ago

3 0

Answer

32 is the answer....

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What is the difference?

Ganezh [65]

Answer:

$\frac{x^2+4x-1}{x(x+2)}$

Step-by-step explanation:

Given

$\frac{x+5}{x+2}$ - $\frac{x+1}{x^2+2x}$ ← factor denominator

= $\frac{x+5}{x+2}$ - $\frac{x+1}{x(x+2)}$

We require the fractions to have a common denominator.

Multiply numerator/denominator of first fraction by x

= $\frac{x(x+5)}{x(x+2)}$ - $\frac{x+1}{x(x+2)}$

Subtract terms on numerator leaving the common denominator

= $\frac{x^2+5x-x-1}{x(x+2)}$

= $\frac{x^2+4x-1}{x(x+2)}$

7 0

2 years ago

Its so easy Whats 1 + 1 = ?

Anika [276]

Answer:

1+1=2....................

4 0

2 years ago

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Solve 2x2 - 126 = 0. Make sure to simplify if necessary.

grandymaker [24]

-122

sorry if i am wrong but have a good day<3

8 0

2 years ago

20 points

gavmur [86]

Answer:

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2 years ago

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What is the value of x? A. 4 B. 4√3 C. 8 D. 8√3

SashulF [63]

Answer:

B. 4√3

Step-by-step explanation:

$\sin \: 60 \degree = \frac{x}{8} \\ \\ \therefore \: \frac{ \sqrt{3} }{2} = \frac{x}{8} \\ \\ \therefore \: x = \frac{8 \times \sqrt{3} }{2} \\ \\ \therefore \: x = 4 \times \sqrt{3}\\ \\ \huge \purple{ \boxed{ \therefore \: x = 4 \sqrt{3} }}\\$

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3 years ago