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2 years ago

Find the the equation of the line passing through the points (3,3) and (4, 5)

Mathematics

1 answer:

Nostrana [21]2 years ago

6 0

Answer:

y = 2x - 3

Step-by-step explanation:

Given:

(3, 3) and (4, 5)

Solve:

Find the slope (m) between the two points:

m = (y2 - y1)/(y2 - 1)

(x1, y1) = (3, 3)

(x2, y2) = (4, 5)

m = (5 - 3)/(4 - 3)

= 2/1

m = 2

Slope-intercept form (y = mx + a):

y = 2x + a

To find a, plug in one of the points into the equation:

3 = 2(3) + a

3 = 6 + a

3 - 6 = a

a = -3

y = 2x - 3

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Can someone please help me with this problem? You need to find the value of x and y by using the strategy of ELIMINATION. Please

Setler [38]

Answer:

x = 136/35; y = -⁹/₁₀

Step-by-step explanation:

(1) 7x + 8y = 20

(2) 7x – 2y = 29 Subtract (2) from (1)

10y = -9 Divide each side by 10

(3) y = -⁹/₁₀ Substitute (3) into (1)

7x - 2(-⁹/₁₀) = 29

7x + 18/10 = 29 Subtract 18/10 from each side

7x = 29 - 18/10

7x = (290 - 18)/10

7x = 272/10 Divide each side by 7

x = 272/70

x = 136/35

x = 136/35; y = -⁹/₁₀

Check:

(1) 7(136/35) + 8(-⁹/₁₀) = 20

136/5 - 72/10 = 20

136/5 - 36/5 = 20

100/5 = 20

20 = 20

(2) 7(136/35) – 2(-⁹/₁₀) = 29

136/5 + 18/10 = 29

136/5 + ⁹/₅ = 29

145/5 = 29

29 = 29

5 0

2 years ago

What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$

Simplifying the terms, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}$

Multiplying, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}$

Adding the like terms, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}$

Thus, the product of the given expression is $104 x^{4}+16 \sqrt{30} x^{4}$

7 0

3 years ago

Help me out please!!!!

Citrus2011 [14]

Answer : y - 1 = 1/2 (x-3)

The formula for point slope is y - y1 = m (x - x1)
M is the slope of the line. The nine and three come from the point given. I used the point (3, 1). Hope this helps !

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2 years ago

The number of times the people in a group surveyed on the street have gone to the cinema this month are:

Tcecarenko [31]

I will help you do it not give the answer,
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I know it’s confusing at first but just keep trying
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If it doesn’t I will explain again.
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2 years ago

How many different ways can six runners line up in a race?

xz_007 [3.2K]

Six runners can line up 36 different ways

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2 years ago