Question

A 16-inch diameter (8-inch radius) car tire is one of the most popular sizes for today's car Find the number of revolutions made by a tire with a radius of 8
inches that travels 5,280 feet (or 1 mile). Use 3.14 for Round your answer to the nearest tenth of a revolution.

Answer 1

Answer:

1261.1 revolutions

Step-by-step explanation:

Given

$d = 16in$ --- the diameter

$Distance = 5280ft$

Required

The number of revolution completer

First, calculate the circumference (c) of the tire

$c = \pi d$

$c = 3.14 * 16$

$c = 50.24$

Let the number of revolutions be n.

The product of n and the circumference equals to the total distance travelled.

So:

$c * n = 5280 ft$

$50.24in* n = 5280 ft$

Make n the subject

$n = \frac{5280 ft}{50.24in}$

Convert feet to inch

$n = \frac{5280 *12in}{50.24in}$

$n = \frac{63360in}{50.24in}$

$n = \frac{63360}{50.24}$

Solve for n

$n = 1261.14649682$

Approximate

$n = 1261.1$