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Shtirlitz [24]
3 years ago
6

Why are the layers of the atmospher in the order that they are in?

Physics
1 answer:
aliya0001 [1]3 years ago
4 0

Answer:

<em><u>TROPOSPHERE</u></em><em><u> </u></em><em>the</em><em> </em><em>lowest</em><em> </em><em>layer</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>atmosphere</em><em> </em><em>closest</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>earth</em>

<em><u>STRATOSPHERE</u></em><em><u> </u></em><em>constant</em><em> </em><em>temperature</em><em> </em>

<em>MESOSPHERE</em><em> </em><em>layer</em><em> </em><em>with</em><em> </em><em>the</em><em> </em><em>strongest</em><em> </em><em>wind</em><em> </em><em>and</em><em> </em><em>below</em><em> </em><em>the</em><em> </em><em>themosphere</em>

<em><u>Themosphere</u></em><em><u> </u></em><em>a</em><em>bsorbs</em><em> </em><em>UV</em><em> </em><em>radiation</em><em> </em>

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The force diagram shown here describes the forces that external objects (the surface andEarth) exert on a woman (in this scenari
sveticcg [70]

The three different motions are;

  • The upward motion of the woman is constant
  • The downward motion of the woman is also constant
  • The horizontal motion of the woman is zero.

<h3>What is force diagram?</h3>

Force diagram is a pictorial or graphical illustration of different forces acting on object.

In this given question, there two forces acting on the woman as depicted in the force diagram.

  • The first force is surface force (Fs)
  • The second force is force of Earth (FE)

In the given force diagram, the woman is in equilibrium, this implies that the surface force and the Earth force are equal.

The three different types of motion of the woman that are consistent with the force diagram include the following;

  • The upward motion of the woman is constant
  • The downward motion of the woman is also constant
  • The horizontal motion of the woman is zero since there is no horizontal force on the woman.

Learn more about force diagram here: brainly.com/question/3624253

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4 0
1 year ago
When a golf club hits a 0.0459 kg ball at rest, it exerts a 2380 N force for 0.00100 s. What is the speed of the ball afterwards
aksik [14]

Answer:

51.85m/s

Explanation:

Given parameters:

Mass of ball  = 0.0459kg

Force  = 2380N

Time taken  = 0.001s

Unknown:

Speed of the ball afterwards  = ?

Solution:

To solve this problem, we use Newton's second law of motion:

   F = m x \frac{v - u}{t}  

F is the force

m is the mass

v is the final velocity

u is the initial velocity

t is the time taken

        2380  = 0.0459 x \frac{v- 0}{0.001}  

        0.0459v  = 2.38

                   v = 51.85m/s

8 0
3 years ago
Read 2 more answers
Which shows the correct lens equation? The inverse of f equals the inverse of d Subscript o Baseline times the inverse of d Subs
musickatia [10]

Answer:

The inverse of f equals the inverse of d Subscript o Baseline plus the inverse of d Subscript I Baseline.

Explanation:

The lens equation shows the relation among focal length of the lens, image distance and object distance. It can be expressed as:

  \frac{1}{f} = \frac{1}{d_{o} } + \frac{1}{d_{I} }

where: f is the focal length of the lens, d_{o} is the object distance to the lens and d_{I} is the image distance to the lens.

The lens equation can be used to determine the unknown value among the variables f , d_{o} and d_{o}.

6 0
3 years ago
Read 2 more answers
The sound source of a ship’s sonar system operates at a frequency of 22.0 kHz . The speed of sound in water (assumed to be at a
Degger [83]

Answer:

147.456077993 Hz

Explanation:

f_0 = Frequency of the sonar = 22 kHz

v_w = Velocity of the whale = 4.95 m/s

v = Speed of sound in water = 1482 m/s

The difference in frequency is given by

\Delta f=f_0\times\dfrac{2v_{w}}{v-v_w}\\\Rightarrow \Delta f=22000\times\dfrac{2\times 4.95}{1482-4.95}\\\Rightarrow \Delta f=147.456077993\ Hz

The difference in frequency is 147.456077993 Hz

6 0
3 years ago
Describe how you could measure the thickness of paper with an ordinary ruler
Svetllana [295]
Measure a whole stack (one in which you know the number of sheets), then divide your measurement by the number of sheets in that stack
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