Wavelength = (speed) / (frequency) = (460 m/s) / (230/sec) = <em>2 meters</em>
Answer:
Time period of the osculation will be 0.0671 sec
Explanation:
It is given a vertical spring is stretched by 4 cm
So change in length of the spring x = 4 cm = 0.04 m
Mass which is hung from it m = 12 gram = 0.012 kg
Sprig force will be equal to weight of the mass
So 

k = 244.7 N/m
Now new mass is m = 28 gram = 0.028 kg
So time period with new mass will be


V = u + at
<span>= 0 + (9.81)(10) </span>
<span>= 98.1m/s </span>
<span>Ignoring air resistance.</span>