F=Gm1m2/r^2 where G is a gravitational constant
F≈m
the greater the mass of planets, the greater the gravitation force experiment by a person
gravity of a planet (a=GM/r^2)
the larger the mass of planet , the larger the gravity of planet
Weight = mass * gravity of the planet
therefore when neutron star has the same mass as our sun, the mass is larger and the gravity of it will be very large
Answer
given,
mass of disk = 2 Kg
radius = 0.1 m
time = 10 sec
a) 800 rpm to rad/s
=
=
b) 740 rpm to rad/s
=
=
c) Angular acceleration
d) moment of inertia of disc
I = 0.01 Kg.m²
e) τ = I α
τ = 0.01 x 0.629
τ = 6.29 x 10⁻³ N.m
f) impulse = Force x time
J = 0.629 Ns
g) Work done
W = Δ KE
W = 5.07 J
First, let's convert the initial speed of the rhino:
The acceleration of the rhino is given by:
where the negative sign means it is a deceleration. We can neglect the negative sign since we are interested only in the magnitude of the force applied, which is given by Netwon's second law:
This should include distances. Displacement is the shortest distance from point A to point B. Distance is the total length of travel. For an example I have included a simple map.
Displacement would not be an accurate representation of the driving instructions because it would not tell the total length of travel. Basically, the driver would be going through buildings if you told them displacement. Directions would tell them the roads traveled.