All categories

2 years ago

a sound wave is determined to have a frequency of 1,000 hz and wavelength of 35cm. what is the speed of this wave?

Physics

1 answer:

natulia [17]2 years ago

3 0

Answer:

The speed of the sound wave is 350 m $s^{-1}$

Explanation:

Given

Frequency of sound wave = 1000Hz = 1000 $s^{-1}$ (since 1 $s^{-1}$ = 1 Hertz (Hz))

Wavelength of sound wave = 35 cm

Speed of sound wave = ?

All waves have same the relation among frequency, sound and speed which is given by

v=fλ , where

v is the speed

f is frequency

λ is wavelength

Therefore, the speed of sound wave = 1000 $s^{-1}$ x 35 cm

= 35000 cm $s^{-1}$

= 350 m $s^{-1}$

Hence the speed of the sound wave is 350 m $s^{-1}$

You might be interested in

What is the radius of the 5th orbital in hydrogen?

iren2701 [21]

Answer:

So, the radius of fifth Bohr orbital of hydrogen is 1. 3225 nm.

Explanation:

pls mark me brainless hope this helps loves x!

6 0

1 year ago

Read 2 more answers

If you're driving towards the sun late in the afternoon, you can reduce the glare from the road by wearing sunglasses that permi

AveGali [126]

Correct answer choice is:

C. Polarized in a vertical plane.

Explanation:

Polarized sunglasses give excellent glare shield, particularly on the water. Polarized lenses include a specific filter that prevents this type of strong reflected light, diminishing glare.

This is because when you angle one polarized lens to different perpendicularly, they prevent glare both horizontally and vertically. The polarized lenses are enduringly tinted sunglasses that exceedingly decrease glare.

7 0

2 years ago

Leia is presenting her project about gravity to her class. She says that both mass and distance affect how strong the gravitatio

DaniilM [7]

Answer:

No, because as distance increases, gravitional force decreases.

5 0

3 years ago

What can be found by counting the number of troughs per second in a wave diagram

zysi [14]

Frequency,................

4 0

2 years ago

Read 2 more answers

A golfer imparts a speed of 30.3 m/s to a ball, and it travels the maximum possible distance before landing on the green. the te

sergey [27]

<u>Answer:</u>

a) Time spend by ball in air = 4.368 seconds

b) Longest hole that golfer can make = 93.59 meter

<u>Explanation:</u>

Projectile motion has two types of motion Horizontal and Vertical motion.

Vertical motion:

We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

Considering upward vertical motion of projectile.

In this case, Initial velocity = vertical component of velocity = u sin θ, acceleration = acceleration due to gravity = -g $m/s^2$ and final velocity = 0 m/s.

0 = u sin θ - gt

t = u sin θ/g

Total time for vertical motion is two times time taken for upward vertical motion of projectile.

So total travel time of projectile = 2u sin θ/g

Horizontal motion:

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this case Initial velocity = horizontal component of velocity = u cos θ, acceleration = 0 $m/s^2$ and time taken = 2u sin θ /g

So range of projectile, $R=ucos\theta*\frac{2u sin\theta}{g} = \frac{u^2sin2\theta}{g}$

a) We have golf ball travels maximum distance, so range is maximum.

Maximum range is when, sin 2θ =1

=> θ = 45⁰

Now we have travel time of projectile, t = 2u sin θ/g

Initial velocity = 30.3 m/s and θ = 45⁰

So time spend in air, t = $\frac{2*30.3*sin45}{9.81} =4.368 seconds$

b) Longest hole that golfer can make = Range of projectile = $\frac{u^2sin2\theta}{g}$

Longest hole that golfer can make = $\frac{30.3^2sin(2*45)}{9.81}=93.59 meter$

4 0

2 years ago