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3 years ago

What is the mass of 12,000cm3 of N2? Explain your answer?

Chemistry

1 answer:

Damm [24]3 years ago

8 0

Answer:

14g

Explanation:

assuming that N2 is a gas, use the gas formula ( mole = volume/24) to find the number of moles

then once you have found the moles (0.5 mol) use the (mole = mass/mr) formula to find the mass

so, 0.5 x 28 = 14g

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calculate the mass of calcium phosphate and the mass of sodium chloride that could be formed when a solution containing 12.00g o

Leviafan [203]

Answer : The mass of calcium phosphate and the mass of sodium chloride that formed could be, 9.3 and 10.5 grams respectively.

Explanation : Given,

Mass of $Na_3PO_4$ = 12.00 g

Mass of $CaCl_2$ = 10.0 g

Molar mass of $Na_3PO_4$ = 164 g/mol

Molar mass of $CaCl_2$ = 111 g/mol

Molar mass of $NaCl$ = 58.5 g/mol

Molar mass of $Ca_3(PO_4)_2$ = 310 g/mol

First we have to calculate the moles of $Na_3PO_4$ and $CaCl_2$ .

$\text{Moles of }Na_3PO_4=\frac{\text{Given mass }Na_3PO_4}{\text{Molar mass }Na_3PO_4}$

$\text{Moles of }Na_3PO_4=\frac{12.00g}{164g/mol}=0.0732mol$

and,

$\text{Moles of }CaCl_2=\frac{\text{Given mass }CaCl_2}{\text{Molar mass }CaCl_2}$

$\text{Moles of }CaCl_2=\frac{10.0g}{111g/mol}=0.0901mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is:

$2Na_3PO_4+3CaCl_2\rightarrow 6NaCl+Ca_3(PO_4)_2$

From the balanced reaction we conclude that

As, 3 mole of $CaCl_2$ react with 2 mole of $Na_3PO_4$

So, 0.0901 moles of $CaCl_2$ react with $\frac{2}{3}\times 0.0901=0.0601$ moles of $Na_3PO_4$

From this we conclude that, $Na_3PO_4$ is an excess reagent because the given moles are greater than the required moles and $CaCl_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $NaCl$ and $Ca_3(PO_4)_2$

From the reaction, we conclude that

As, 3 mole of $CaCl_2$ react to give 6 mole of $NaCl$

So, 0.0901 mole of $CaCl_2$ react to give $\frac{6}{3}\times 0.0901=0.1802$ mole of $NaCl$

and,

As, 3 mole of $CaCl_2$ react to give 1 mole of $Ca_3(PO_4)_2$

So, 0.0901 mole of $CaCl_2$ react to give $\frac{1}{3}\times 0.0901=0.030$ mole of $Ca_3(PO_4)_2$

Now we have to calculate the mass of $NaCl$ and $Ca_3(PO_4)_2$

$\text{ Mass of }NaCl=\text{ Moles of }NaCl\times \text{ Molar mass of }NaCl$

$\text{ Mass of }NaCl=(0.1802moles)\times (58.5g/mole)=10.5g$

and,

$\text{ Mass of }Ca_3(PO_4)_2=\text{ Moles of }Ca_3(PO_4)_2\times \text{ Molar mass of }Ca_3(PO_4)_2$

$\text{ Mass of }Ca_3(PO_4)_2=(0.030moles)\times (310g/mole)=9.3g$

Therefore, the mass of calcium phosphate and the mass of sodium chloride that formed could be, 9.3 and 10.5 grams respectively.

5 0

2 years ago

How many seconds are there in 23 days ?

Brrunno [24]

Since there are 23 days and 24 hours in each day, you multi-ply them and get 552 hours. Since each hours is 60 minutes, 552*60 is 33120 minutes. Since one minute is 60 seconds, 60*33120 is 1,987,200 seconds. Therefore, there are 1,987,200 seconds in 23 days.

7 0

2 years ago

A scientist carries out a reaction twice. In Trial A, the scientist combines the reactants in a container. In Trial B, the scien

Paha777 [63]

It would be C because It will have a lower activation energy than Trial A.

7 0

3 years ago

Read 2 more answers

Use the IUPAC nomenclature rules to give the name for Mg(ClO4)2

Makovka662 [10]

Answer:

The answer to your question is Magnesium Perchlorate

Explanation:

IUPAC Rules to name ternary salts of chlorine

1.- Ternary salts use prefixes and suffixes it depends on the number of oxygens they have.

Example

Metal + Chlorine + 1 oxygen = Name of the metal + hipo chlor + ite

Metal + Chlorine + 2 oxygens = Name of the metal + chlor + ite

Metal + Chlorine + 3 oxygens = Name of the metal + chlor + ate

Metal + Chlorine + 4 oxygens = Name of the metal + per + chlor + ate

For this compound the name is Magnesium Perchlorate.

6 0

2 years ago

Blank is how strong gravity pulls on an object

zheka24 [161]

It is either netforce or gforce

3 0

3 years ago