The combinations of Strontium and chlorine that are possible are only those in which strontium and chlorine combine in the ratio of 1:2.
1) The possible combinations are
- 4 strontium atoms and 8 chlorine
strontium atoms and
chlorine atoms
2) The combinations that are not possible are
- 20 strontium atoms and 60 chlorine atoms
- 130 billion strontium atoms and 195 billion chlorine
We have to work out the ratio of Strontium and chlorine in each of the given combinations in the question. Only the combinations in which the ratio of Strontium and chlorine is 1:2 is possible.
First case:
4 strontium atoms and 8 chlorine atoms gives a Strontium and chlorine ratio of 1:2 so it is possible.
Second case:
20 strontium atoms and 60 chlorine atoms gives a Strontium and chlorine ratio of 1:3 hence it is not possible.
Third case:
strontium atoms and
chlorine atoms gives a Strontium and chlorine ratio of 1:2 hence it is possible.
Fourth case:
130 billion strontium atoms and 195 billion chlorine atoms gives a Strontium and chlorine ratio of 1:1.5 hence it is not possible.
Learn more: brainly.com/question/9743981
Explanation:
A. Hydrogen bonding is present in CS2 but not in CO2.
B. CS2 has greater dipole moment than CO2 and thus the dipole-dipole forces in CS2 are stronger.
C. CS2 partly dissociates to form ions and CO2 does not. Therefore, ion-dipole interactions are present in CS2 but not in CO2.
D. The dispersion forces are greater in CS2 than in CO2.
<u><em>PLS MARK BRAINLIEST :D</em></u>
If it was warn - hot water, i would say yes
the warm - hot water would dissolve because of the temperature
Answer:
9.96*10^21
Explanation:
Molar mass of K2O=29*2+16
= 74g per mol
number of moles in the sample= 1.224/ 74
=0.1654
Number of particles in 1 mole=6.0221409*10^23
Number of particles= 0.01654*6.0221409*10^23
=9.96*10^21
The pressure is 19.3 N/cm².
<em>p</em> = (28.0 lb/1 in²) × (4.45 N/1 lb) × (1 in²/6.45 cm²) = 19.3 N/cm²