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3 years ago

Help ........,,,,.........

Chemistry

1 answer:

stiks02 [169]3 years ago

7 0

<h3>Given :-</h3>

Mass % of carbon (C) = 42.8%
Mass % of oxygen (O) = 57.1%

Empirical formula.

<h3>Solution :- </h3>

◆ Atomic mass of carbon (C) = 12g

◆ Atomic mass of oxygen (O) = 16g

No of moles of carbon (C) = 42.8/12

= 3.57

No of moles of oxygen (O) = 57.1/16

= 3.57

Simplest ratio :-

= 3.57 : 3.57

= 1 : 1

Empirical Formula = CO

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