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Eddi Din [679]
3 years ago
12

Help ........,,,,.........

Chemistry
1 answer:
stiks02 [169]3 years ago
7 0
<h3>Given :-</h3>
  • Mass % of carbon (C) = 42.8%
  • Mass % of oxygen (O) = 57.1%

<h3>To Find :-</h3>
  • Empirical formula.

<h3>Solution :- </h3>

◆ Atomic mass of carbon (C) = 12g

◆ Atomic mass of oxygen (O) = 16g

  • No of moles of carbon (C) = 42.8/12

= 3.57

  • No of moles of oxygen (O) = 57.1/16

= 3.57

Simplest ratio :-

= 3.57 : 3.57

= 1 : 1

Empirical Formula = CO

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