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Dmitry_Shevchenko [17]
3 years ago
13

The movement of water both on and above Earths surface

Chemistry
1 answer:
DanielleElmas [232]3 years ago
4 0

The movement of water on and above the earth's surface is called the hydrologic cycle, or the water cycle. Hope this helps!

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Diagonal lines in the graph represent the temperature of the substance is ___.
labwork [276]
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4 years ago
Hydrochloric acid reacts with sodium hydroxide to form water and sodium chloride.Hydrochloric acids is an extremely acidic,clear
Luden [163]

Answer:

Hydrochloric acid is a strong acid with a distinct pungent smell and it is highly reactive while Sodium hydroxide is a strong base and it is fully Ionic

6 0
3 years ago
Dipole-dipole interactions are (weaker than, stronger than, equal to) hydrogen bonds.
kozerog [31]

Answer and Explanation:

Dipole-Dipole interactions are <u>weaker than</u> hydrogen bonds.

Hydrogen bonds are a form of dipole-dipole interactions, being the strongest form of dipole-dipole interactions.

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7 0
3 years ago
Để trung hoà 20ml dung dịch HCl 0.1M cần 10ml dung dịch NaOH nồng độ x mol/l . Giá trị của x là
elena55 [62]

The question is: To neutralize 20ml of 0.1M HCl solution, 10ml of NaOH solution of concentration x mol/l is required. What is the value of x?

Answer: The value of x is 0.2 M.

Explanation:

Given: V_{1} = 20 mL,   M_{1} = 0.1 M

V_{2} = 10 mL,        M_{2} = x

Formula used is as follows.

M_{1}V_{1} = M_{2}V_{2}\\0.1 M \times 20 mL = x \times 10 mL\\x = 0.2 M

Thus, we can conclude that the value of x is 0.2 M.

6 0
3 years ago
A 3.31-g sample of lead nitrate, pb(no3)2, molar mass = 331 g/mol, is heated in an evacuated cylinder with a volume of 2.11 l. t
bearhunter [10]

The equation in this problem is: 2Pb(NO3)2(s) --> 2PbO(s) + 4NO2(g) + O2(g)

And the question is what the pressure in the cylinder is after decomposition and cooling to a temperature of 300 K.

 

Solution:

Moles of Pb (NO3)2 = 3.31/331 = 0.0100 

2 moles of Pb (NO3)2 will decay to mold 4 moles of NO2 and 1 mole of O2. So 0.0100 moles of Pb (NO3)2 will form 0.02 moles of NO2 and 0.00500 moles of O2 

Then use the formula: PV = nRT. 

P = (0.02 + 0.005) * 0.082 * 300 / 1.62 

= 0.380 atm

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7 0
3 years ago
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