Answer:
y² - (K- 2)y + 2k +1 = 0
equal roots means D=0
D= b^2 - 4ac
a=1, b= (k-2), c= 2k+1
so,
(k-2)^2 - 4(1)(2k+1) = 0
=> k^2 +4 - 8k -4 = 0
=> k^2 -8k = 0
=> k^2 = 8k
=> k= 8k/k
=> k = 8
Therefore the answer is k= 8
Hope it helps........
1200 = 100%
35% of 1200 = 420
1200 + 420 = 1620
There are 1620 students enrolled this year.
Answer:
For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:
Null hypothesis (H0): 
Alternative hypothesis (H1): 
And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 200 or no
Step-by-step explanation:
For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:
Null hypothesis (H0): 
Alternative hypothesis (H1): 
And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 2000 or no
Answer:
Step-by-step explanation:
To find the cofactor of
![A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%265%263%5C%5C-7%264%26-1%5C%5C-8%262%261%5Cend%7Barray%7D%5Cright%5D)
We cross out the Row and columns of the respective entries and find the determinant of the remaining
matrix with the alternating signs.
























Therefore in increasing order, we have;
