In which quadrant is theta if the statement is true: Tan theta > 0 and sin theta >0

Mathematics

1 answer:

lisov135 [29]3 years ago

5 0

Quadrant 1 because sin and tan (as well as consine, but not mentioned) are greater than 0 in that quadrant

You might be interested in

1. There are 1,200 students at Woodland Hills Elementary. Approximately 600 of

fenix001 [56]

1,200 divide by 600 = 2 students

2 students multiply by 50% is 100 students.

So, approximately 100 students ride their bicycles home.

(If not correctly, I am truly sorry)

4 0

3 years ago

Lana71 [14]

Answer:

there’s nothing there

Step-by-step explanation:

7 0

3 years ago

18. Solve the quadratic equation by using the graph.<br><br> Look at screenshot

Rasek [7]

Step-by-step explanation:

As seen from the graph, the curve crosses the x-axis when x = -1 and x = 1. The y-intercept of the curve is -1.

Hence, the quadratic equation of the curve is y = x^2 - 1.

3 0

3 years ago

Rachel created 215 pairs of earrings. Material for the earrings were $0.25 a pair. At a craft fair rachel sells all 215 pairs of

Stels [109]

Answer: 14.97 per pair of earrings

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )

Zina [86]

Answer:

$\purple{ \bold{ \tan( \alpha - \beta ) = 1.00701798}}$

Step-by-step explanation:

$\cos( \alpha ) = \frac{ \sqrt{6} }{6} = \frac{1}{ \sqrt{6} } \\ \\ \therefore \: \sin( \alpha ) = \sqrt{1 - { \cos}^{2} ( \alpha ) } \\ \\ = \sqrt{1 - \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} } \\ \\ = \sqrt{1 - {\frac{1}{ {6} }}} \\ \\ = \sqrt{ {\frac{6 - 1}{ {6} }}} \\ \\ \red{\sin( \alpha ) = \sqrt{ { \frac{5}{ {6} }}} } \\ \\ \tan( \alpha ) = \frac{\sin( \alpha ) }{\cos( \alpha ) } = \sqrt{5} \\ \\ \sin( \beta ) = \frac{ \sqrt{2} }{4} \\ \\ \implies \: \cos( \beta ) = \sqrt{ \frac{7}{8} } \\ \\ \tan( \beta ) = \frac{\sin( \beta ) }{\cos( \beta ) } = \frac{1}{ \sqrt{7} } \\ \\ \tan( \alpha - \beta ) = \frac{ \tan \alpha - \tan \beta }{1 + \tan \alpha . \tan \beta} \\ \\ = \frac{ \sqrt{5} - \frac{1}{ \sqrt{7} } }{1 + \sqrt{5} . \frac{1}{ \sqrt{7} } } \\ \\ = \frac{ \sqrt{35} - 1 }{ \sqrt{7} + \sqrt{5} } \\ \\ \purple{ \bold{ \tan( \alpha - \beta ) = 1.00701798}}$

8 0

3 years ago

In which quadrant is theta if the statement is true: Tan theta > 0 and sin theta >0 ​

In which quadrant is theta if the statement is true: Tan theta > 0 and sin theta >0