Answer:
a) 8π
b) 8/3 π
c) 32/5 π
d) 176/15 π 
Step-by-step explanation:
Given lines :  y = √x, y = 2, x = 0.
<u>a) The x-axis </u>
using the shell method 
y = √x = , x = y^2 
h = y^2 , p = y 
vol = ( 2π ) 
      =  
  
∴ Vol = 8π
<u>b) The line y = 2  ( using the shell method )</u>
p = 2 - y 
h = y^2 
vol = ( 2π )  
 
      = 
      = ( 2π ) * [ 2/3 * y^3  - y^4 / 4 ] ²₀ 
∴ Vol  = 8/3 π
<u>c) The y-axis  ( using shell method )</u>
h = 2-y  = h = 2 - √x
p = x 
vol = 
      = 
      = ( 2π ) [x^2 - 2/5*x^5/2 ]⁴₀
 vol = ( 2π ) ( 16/5 ) = 32/5 π
<u>d) The line x = -1    (using shell method )</u>
p = 1 + x 
h = 2√x 
vol = 
Hence   vol =  176/15 π 
attached below is the graphical representation of P and h 
 
        
             
        
        
        
The practice will end at exactly 4:00 .
        
                    
             
        
        
        
Answer:
-p - 8
Step-by-step explanation:
1 - 3p + 2p - 9 = -p - 8
 
        
             
        
        
        
<span>-4,4,-6,6 is your answer </span>