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3 years ago

Which one should I be picking

Mathematics

1 answer:

Lina20 [59]3 years ago

7 0

Answer:

8 cm

Step-by-step explanation:

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A submarine submerged at a depth of -35.35 meters then dives an additional 8.5 meters. What is the submarine's new depth?

Sophie [7]

Answer:

-35.25 - 8.5 = -40.75 meters

Step-by-step explanation:

When talking about a submersion depth of -32.25 meters, that means the submarine has dropped 32.25 meters.

If we add 8.5 meters of additional submersion to that value, we get:

-32.25 meters + (-8.5 meters) = -32.25 meters - 8.5 meters = -40.75 meters.

7 0

3 years ago

Ross needs to buy a countertop for a laundry room. He calculated the area to be 12 square feet. The actual area is 11.8 square f

sweet [91]

The formula for percentage error is:

$\sf{Percentage~ error= \frac{|Approximate ~-~ Actual|}{|Actual|}}$

Ross got the approximate area as 12, while the actual area was 11.8. So, let's plug it in to the formula.

$\sf{Percentage~ error= \frac{|Approximate ~-~ Actual|}{|Actual|}= \frac{|12-11.8|}{|11.8|}= \frac{|0.2|}{|11.8|}= \frac{0.2}{11.8} \approx 0.0169 }$

Multiply 0.0169 by 100 to make it into a percent.

0.0169 * 100 = 1.69%

Ross's percentage error is 1.69%.

4 0

3 years ago

B squared but b= -4

Serga [27]

Answer:

-16

Step-by-step explanation:

It’s simple, if b = -4 then that squared would be -16

Please brainliest

3 0

3 years ago

Read 2 more answers

5. Solve for x. (9x - 16) (3x + 11) (7x - 5) X=

scoundrel [369]

Answer:

X = 10

Step-by-step explanation:

If right give brainliest Please

Hoped this helped

4 0

2 years ago

I NEED THIS FAST a sample of an unknown liquid has a volume of 30.0 mL and a mass of 6 g. whats the density ? show your work and

Doss [256]

Answer:

The density is 0.2g/mL^2.

Step-by-step explanation:

Use the formula: D= $\frac{m}{V}$ (where v=volume, and m=mass). The mass of the liquid is 6g. The volume of the liquid is 30mL.
To determine density, insert the values into the formula ( $D=\frac{6g}{30mL}$ ).
Divide: 6g/30mL= 0.2g/mL^2

6 0

2 years ago