The answer would be 11 because the x's 9 doesnt have to move because they're on the same point. If you take 7 away from -7 you get zero. Add 4 to that 7 and you get 11. Make sesnse?
Hope this helped!
Answer:
132
Step-by-step explanation:
Volume for a rectangular prism is V=lwh. so you do 11*3*4. 11 is the length, 3 is the width and 4 is the height
The purpose of the tensor-on-tensor regression, which we examine, is to relate tensor responses to tensor covariates with a low Tucker rank parameter tensor/matrix without being aware of its intrinsic rank beforehand.
By examining the impact of rank over-parameterization, we suggest the Riemannian Gradient Descent (RGD) and Riemannian Gauss-Newton (RGN) methods to address the problem of unknown rank. By demonstrating that RGD and RGN, respectively, converge linearly and quadratically to a statistically optimal estimate in both rank correctly-parameterized and over-parameterized scenarios, we offer the first convergence guarantee for the generic tensor-on-tensor regression. According to our theory, Riemannian optimization techniques automatically adjust to over-parameterization without requiring implementation changes.
Learn more about tensor-on-tensor here
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Answer:
D. 20°
Step-by-step explanation:
The entire angle = 90 degrees you can tell that from the corner indicator
Set the two expressions equal to 90
(3x+10) + (x) = 90
Combine like terms
4x + 10 = 90
Subtract 10 from both sides to cancel it out
4x = 80
Divide each side by 4
x = 20
Check it by substituting x for 20
3(20) + 10 = 70 x = 20 70 + 20 = 90
Answer:
<h2>(0.3, -18.45).</h2>
Step-by-step explanation:
We need to recur to the extreme value theorem, which states: "If a function is continuous on a closed interval, then that function has a maximum and a minimum inside that interval".
Basically, as the theorem states, if a dunction is continuous, then it has maxium or minium.
In this case, we have a quadratic function, which is a parabola. An important characteristic of parabolas is that they have a maximum or a minium, but they don't have both. When the quadratic term of the fuction is positive, then it has a minium at its vertex. When the quadratic term of the function is negative, then it has a maximum at its vertex.
So, the given function is 
, where the quadratic term is positive, so the functions has a minimum at 
, where 
and 
, let's find that point
<h3>
</h3><h3>
</h3><h3 /><h3>Therefore, the minium of the function is at (0.3, -18.45).</h3>
