Answer: CO is a limiting reagent with regards to the Fe production.
Explanation:
Moles of CO = 
moles of 
According to reaction , 3 mole of CO reacts with 1 mole of 
then , 0.4714 moles of CO will react with : 
moles of that is 0.1571 moles.
0.4714 moles of CO will react with 0.1571 moles of which means that CO is present in limited amount acting as limiting reagent.
Mole remaining of = 0.2673 mol - 0.1571 mol = 0.1102 mol
Hence, CO is a limiting reagent and is an excessive reagent.
Answer:
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Explanation:
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The volume of CO2 at STP =124.298 L
<h3>Further explanation</h3>
Given
Reaction
4 KMnO4, +4 C3H5(OH)5, -7K2CO3, + 7 Mn2O3, +5 CO2, + 16 H2O
701,52 g of KMnO4
Required
volume of CO2 at STP
Solution
mol KMnO4 (MW=158,034 g/mol) :
mol = mass : MW
mol = 701.52 : 158.034
mol = 4.439
mol CO2 from equation : 5/4 x mol KMnO4 = 5/4 x 4.439 = 5.549
At STP 1 mol = 22.4 L, so for 5.549 moles :
=5.549 x 22.4
=124.298 L
The answer would be 20% (B)
