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stich3 [128]
3 years ago
11

Balanced forces act on a ball that is being held above the ground in someone's hand. explain why these forces on the ball are ba

lanced
Physics
1 answer:
Licemer1 [7]3 years ago
3 0
Hi Andrescruz9386

The ball in someone's hand is a balanced force because the object is staying in motion and is not changing at all so its evenly balanced, if its swinging back and fourth it is in motion and it wont stop till it becomes unbalanced, if the ball is just being held above the ground yes its balanced because nothing Is happening to it, its basically like a balance scale, if both sides are even and equal, than nothing will happen because there is no side that has more or less its equal so that's why its balanced, in order for it to be unbalanced it has to be brought upon unbalanced forces.
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Explanation:

Let \textbf{A} = 6\hat{\textbf{i}} + 4\hat{\textbf{j}} - 2\hat{\textbf{k}} and \textbf{B} = 2\hat{\textbf{i}} - 2\hat{\textbf{j}} + 3\hat{\textbf{k}}

The sum of the two vectors is

\textbf{A + B} = (6 + 2)\hat{\textbf{i}} + (4 - 2)\hat{\textbf{j}} + (-2 + 3)\hat{\textbf{k}}

= 8\hat{\textbf{i}} + 2\hat{\textbf{j}} + \hat{\textbf{k}}

The difference between the two vectors can be written as

\textbf{A - B} = (6 - 2)\hat{\textbf{i}} + (4 - (-2))\hat{\textbf{j}} + (-2 - 3)\hat{\textbf{k}}

= 4\hat{\textbf{i}} + 6\hat{\textbf{j}} - 5\hat{\textbf{k}}

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3 years ago
A 2.2kg block of ice slides across a rough floor. Its initial velocity is 2.5m/s and its final velocity is 0.50m/s. How much of
kirill [66]

Answer:A 2.2kg block of ice slides across a rough floor. Its initial velocity is 2.5m/s and its final velocity is 0.50m/s. How much of the ice block melted as a result of the work done by friction? (Latent Heat of water is 3.3*10^5J/kg)

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Answer:

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None of the answer choices except the last one has anything to do with the effect of exploding a satellite. When you are arguing that exploding a satellite is ill conceived, you need to address specifically the effects of exploding the satellite.

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3 years ago
A 60-kg rollerblader rolls 10 m down a 30? incline. When she reaches the level floor at the bottom, she applies the brakes. The
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Answer:

s = 20 m

Explanation:

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using conservation of energy

\dfrac{1}{2}mu^2 = m g d sin \theta

u^2 = 2 g d sin30^0

u= \sqrt{2\times 9.8 \times 10 sin30^0}

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a = μ g

a = 0.25 x 9.8

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