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3 years ago

8

A coach wants her team to have fun, win some games, and be a productive unit. What is the most important personality trait the c

oach should demonstrate to achieve her goals?

2 answers:

Natasha_Volkova [10]3 years ago

6 0

The most important personality trait the coach should demonstrate to achieve her goals is <span>persistence </span>

4vir4ik [10]3 years ago

6 0

The answer is leadership

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If 12 coulombs of electric charge pass a point in 4.0

zubka84 [21]

Answer:

AS

Explanation:

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3 years ago

Which of the following diagrams represent a balanced force

Amanda [17]

I don’t see the diagram :)?

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3 years ago

Robyn has been working out five days a week for the past six months. She is now planning to take a month-long break from the gym

Vsevolod [243]

The answer is C -
because reversibility means when taking a break it'll be hard to get back on schedule

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3 years ago

Consider a uniform solid sphere of radius R and mass M rolling without slipping. Which form of its kinetic energy is larger, tra

castortr0y [4]

Answer:

A. Its translational kinetic energy is larger than its rotational kinetic energy.

Explanation:

Given that

Radius = R

Mass = M

We know that mass moment of inertia for the solid sphere

$I=\dfrac{2}{5}MR^2$

Lets take angular speed =ω

Linear speed =V

Condition for pure rolling , V= ω R

Rotation energy ,RE

$RE=\dfrac{1}{2}I\omega^2$

$RE=\dfrac{1}{2}\times \dfrac{2}{5}MR^2\times \omega^2$

$RE=\dfrac{1}{2}\times \dfrac{2}{5}MR^2\times \omega^2$

$RE=\dfrac{1}{5}\times MR^2\times \omega^2$

$RE=\dfrac{1}{5}\times MV^2$

RE= 0.2 MV²

The transnational kinetic energy TE

$TE=\dfrac{1}{2}MV^2$

TE= 0.5 MV²

From above we can say that transnational energy is more than rotational energy.

Therefore the answer is A.

3 0

3 years ago

Suppose a car is traveling at +25.0 m/s, and the driver sees a traffic light turn red. After 0.340 s has elapsed (the reaction t

scoundrel [369]

First, we will get the distance traveled before the driver applied the brakes.
distance = velocity * time
distance = 25*0.34 = 8.5 m

Now, we will calculated the distance that the car traveled after the driver applied the brakes. To do this, we will use the equation of motion:
<span>vf^2 = vi^2 + 2*a*d where:
</span>vf = zero, vi = 25 m/s and a = -7 m/s^2
Note: The negative sign is only to show deceleration
d = <span> 1/2*(625) /(7) = 44.6428 m

The total stopping distance =</span> 8.5 + 44.6428 = 53.1428 m

3 0

3 years ago