Question

a transformer has 1,400 turns in the primary coil and 100 turns in the secondary coil. if the primary coil is connected to a 120 v outlet and draw 0.04 a, what is the current of the secondary coil?

Answer 1

0.56 A is the current of the secondary coil.

transformer is the device that transfer electric energy from one AC circuit to another.

we know that ;

I ∝ 1/n;

where I IS CURRENT and n is NUMBER OF TURNS.

(I) secondary = X A

(n) secondary = 100

(I)  primary  = 0.04 A

(n)  primary  = 1400

USING THIS-----> I ∝ 1/n;

=>

0.04 A/X A =100/1400

=>X=0.56 A

as the current in the transformer is inversely proportional to the number of turns so 0.56 A is the current in the secondary coil.

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