Answer:
The net Electric field at the mid point is 289.19 N/C
Given:
Q = + 71 nC = 
Q' = + 42 nC = 
Separation distance, d = 1.9 m
Solution:
To find the magnitude of electric field at the mid point,
Electric field at the mid-point due to charge Q is given by:



Now,
Electric field at the mid-point due to charge Q' is given by:



Now,
The net Electric field is given by:


A person is submerged of about 97.9%.
The average density of the human body is given as 979 kg/ m³.
<h3>Define Law of floatation.</h3>
Law of floatation can be defined as the volume of the liquid displaced when a body floats on the liquid surface is equal to the body submerged in the water.
As body has the stable equilibrium state, the buoyancy of the fluid will be equal to the weight.
Weight of the body floating = Weight of the body immersed in fluid
Law of floatation = Density of the floating object / density of fluid
As fluid is the freshwater here, the density of fluid will be 1000 kg/ m³.
= (979 kg/ m³) / ( 1000 kg/ m³)
= 97.9 %
A person is submerged when floating gently in fresh water about 97.9%.
Learn more about law of floatation,
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Answer:
yes
Explanation:
masses attract each other
with a teeny-tiny force
Answer:
Sam is providing the biggest power i.e. 50 W
Explanation:
Sam is moving house and is carrying a 300N box of books up a flight of steps 5m high, it takes her 30 seconds.
Sam's power :

Gary follows her carrying a bag of clothes doing 1000 J of work; it only takes him 25 seconds.
Gary's power :

So, it is clear that Sam is providing the biggest power.