An unusual lightning strike has a vertical portion with a current of –400 A downwards. The Earth’s magnetic field at that locati
1 answer:
Answer:
The magnetic force is 0.3 N.
Explanation:
Given that,
Current in an unusual lightning strike, I = -400 A
The Earth’s magnetic field at that location is parallel to the ground and has a magnitude of 30 μT,
We need to find the force exerted by the Earth’s magnetic field on the 25 m-long current.
The magnetic force is given by :
So, the magnetic force is 0.3 N.
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Answer:
Explanation:
As we know that the speed of sound in air is given as
now the rate of strike is 1 stroke per second
so distance is given as
now we will have
so the distance is given as
Answer:
The magnitude of the magnetic field is 1.83 x T.
Explanation:
The flow of an electric current in a straight wire induces magnetic field around the wire. When current is flowing through two wires in the same direction, a force of attraction exists between the wires. But if the current flows in opposite directions, the force of repulsion is felt by the wires.
In the given question, the direction of flow of current through the wires is opposite, thus both wires applies the same field on each other. The result to repulsion between them.
The magnetic field (B) between the given wires can be determined by:
B =
where: I is the current, r is the distance between the wires and is the magnetic field constant.
But, I = 11 A, r = 0.12 m and = 4
x
Tm/A
So that;
B =
= 1.8333 x
B = 1.83 x T
Explanation:
It is given that,
Radius of the circular orbit,
Speed of the electron,
Mass of the electron,
(a) The force acting on the electron is centripetal force. Its formula is given by :
(b) The centripetal acceleration of the electron is given by :
Hence, this is the required solution.
1) Gravitational potential energy
In fact, gravitational potential energy is given by:
where m is the mass of the roller coaster, g is the gravitational acceleration and h is the heigth. Therefore, when the roller coaster goes uphill, the height h increases and the roller coaster gains gravitational potential energy.
2) The relationship between potential and kinetic energy is:
where ME is the total mechanical energy, KE is the kinetic energy, GPE is the gravitational potential energy. Since the value of ME is constant (when no friction is present), this means that when KE increases, GPE decreases, and vice-versa.
3) If friction is removed from the track, the roller coaster would move forever. In fact, in the equation written in part 2), ME is constant only in case there is no friction - when friction is present, part of the energy is lost due to the friction, so the total ME available decreases little by little until it becomes zero, and the roller coaster cannot move anymore.
4) It matters because it affects the magnitude of the friction. In fact, friction is given by
where is the coefficient of friction, m is the mass ,and g the gravitational acceleration. When the number of carts is increased, the mass increases, therefore the friction increases as well.