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solmaris [256]
3 years ago
15

An unusual lightning strike has a vertical portion with a current of –400 A downwards. The Earth’s magnetic field at that locati

on is parallel to the ground and has a magnitude of 30 μT. In units of N (Newtons), the force exerted by the Earth’s magnetic field on the 25 m-long current is
Physics
1 answer:
marusya05 [52]3 years ago
8 0

Answer:

The magnetic force is 0.3 N.        

Explanation:

Given that,

Current in an unusual lightning strike, I = -400 A

The Earth’s magnetic field at that location is parallel to the ground and has a magnitude of 30 μT, B=30\times 10^{-6}\ T

We need to find the force exerted by the Earth’s magnetic field on the 25 m-long current.

The magnetic force is given by :

F=ILB\\\\F=400\times 25\times 30\times 10^{-6}\\\\F=0.3\ N

So, the magnetic force is 0.3 N.

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A skateboarder jumps horizontally off the top of a staircase and lands at bottom of the stairs. The staircase has a horizontal l
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Answer:

The vertical velocity of the skater upon landing is 10.788 meters per second.

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Skateboarder experiments a parabolic movement. As skateboarder jumps horizontally off the top of the staircase, it means that vertical component of initial velocity is zero and accelerates by gravity, the final vertical speed is calculated by the following expression:

v = v_{o} + g\cdot t

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t - Time, measured in seconds.

Given that v_{o} = 0\,\frac{m}{s}, g = -9.807\,\frac{m}{s^{2}} and t = 1.10\,s, the final velocity of the skater upon landing is:

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The vertical velocity of the skater upon landing is 10.788 meters per second.

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3 years ago
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