Answer:
Net charge contained in the cubeq= 3.536×10^-6C
Explanation:
Formular for total flux in a cube is given as:
Total flux= E300Acos(180) + E200Acos(0)
Where A is crossectional area
Total flux= A(E200-E300)
Total flux= q/Eo
q= Eo×total flux
q=(8.84×10^-12)×(100)^2×(100-60)
q= 3.536×10^-6C
Displacement (between time 0 and time 25) is the area under the velocity time curve, i.e. ∫ vdt.
Here, v(0)=10, v(25)=34 (approx.)
Therefore
displacement = (1/2)(10+34 m/s)*(25-0) s [ trapezoid area ]
=550 m
A proton has a positive (1+) charge
Answer:
5 L
Explanation:
Ideal gas law:
PV = nRT
If P, n, and R are constant, then:
n₁R/P₁ = n₂R/P₂
Using ideal gas law, we can rewrite this as:
V₁/T₁ = V₂/T₂
This is known as Charles' law.
Plugging in values:
10 L / 546 K = V / 273 K
V = 5 L
Answer:
The bending moment is 459.16 N.m
Explanation:
From the given information;
Let's assume that the angle is 66°
Then, the free body diagram is draw and attached in the file below.
Now, the calculation of the acceleration from the first part of the free body diagram is:

Bending moment M:
From the second part of the diagram:
