Question

Chemistry Question, Don't really know how to do it lol.

Answer 1

Answer: 17.2 g

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} HgS=\frac{20.0 g}{233g/mol}=0.085moles$

The balanced chemical equation is:

$4HgS(s)+4CaO(s)\rightarrow 4Hg(l)+3CaS(s))+CaSO_4(s)$  

According to stoichiometry :  

4 moles of $HgS$ produce =  4 moles of $Hg$

Thus 0.085 moles of $HgS$ will require=$\frac{4}{4}\times 0.085=0.085moles$  of $Hg$

Mass of $Hg=moles\times {\text {Molar mass}}=0.085moles\times 200.6g/mol=17.2g$

Thus 17.2 g of $Hg$ will be produced form 20.0 g of HgS.