13
Al
Aluminum
Atomic mass 26.982
Answer: D.Aluminium Oxide 0.10, Magnesium Oxide 0.50
Explanation:
Number of moles of NaOH= number of moles × volume
Number of moles= 100/1000 × 2 = 0.2 moles
Since;
2 moles of NaOH yield 1 mole of Al2O3
0.2 moles of NaOH will yield 0.2 × 1/2 = 0.1 moles of Al2O3.
Number of moles of HCl= 800/1000 × 2 = 1.6 moles
If 1 mole of Al2O3 requires 6 moles of HCl
0.1 moles of Al2O3 requires 0.1 × 6 = 0.6 moles of HCl.
Number of moles of HCl left after reaction with Al2O3 = 1.6- 0.6 = 1 mole
This leftover reacts with MgO
But;
1 mole of MgO reacts with 2 moles of HCl
x moles of MgO reacts with 1 mole of HCl
Thus; x= 0.5 moles of MgO
Answer:
<u><em>The correct answer is : </em></u>
a silver nitrate solution (AgNO3) is mixed with a solution of magnesium bromide (MgBr2). The balanced reaction would be: 2 AgNO3(aq) + MgBr2 --> 2 AgBr + Mg(NO3)2
<u><em>the last one </em></u>
Answer is: molality is 5.87 m.
ω(HNO₃) = 27.0% = 0.27.
If we use mass of solution 100 grams:
m(solution) = 100 g.
m(HNO₃) = ω(HNO₃) · m(solution).
m(HNO₃) = 0.27 · 100 g.
m(HNO₃) = 27 g.
n(HNO₃) = m(HNO₃) ÷ M(HNO₃).
n(HNO₃) = 27 g ÷ 63 g/mol.
n(HNO₃) = 0.428 mol.
m(H₂O) = 100 g - 27 g.
m(H₂O) = 73 g ÷ 1000 g/kg.
m(H₂O) = 0.073 kg.
b(solution) = n(HNO₃) ÷ m(H₂O).
b(solution) = 0.428 mol ÷ 0.073 kg.
b(solution) = 5.87 mol/kg = 5.87 m.
Answer:
Conversely, as one progresses down a group on the periodic table, the ionization energy will likely decrease since the valence electrons are farther away from the nucleus and experience greater shielding. They experience a weaker attraction to the positive charge of the nucleus.
