The answer is six because it is in group six A on the periodic table.
Answer:
add 7.5L of water
Explanation:
M1×V1=M2×V2
M is molarity, V is volume
0.7 × 10 = 0.4 × V2
V2= 17.5L
vol. of water to add= 17.5 - 10 = 7.5L
The atomic radius increases down a column (group) and decreases along a row
Answer:
OptionA. 2C4H10 + 13O2 —> 8CO2 + 10H20
Explanation:
Butane burns is air (O2) according to the equation:
C4H10 + O2 —> CO2 + H20
Considering the equation, it is evident that it not balanced. Now let us balance the equation as shown below;
There are a total of 4 carbon atoms on the left and 1 carbon atom on the right. It can be balanced by putting 4 in front of CO2 as shown below:
C4H10 + O2 —> 4CO2 + H20
Next, there are 10 hydrogen atoms on the left and 2 hydrogen atoms on the right. Therefore to balance it, put 5 in front of H2O as shown below:
C4H10 + O2 —> 4CO2 + 5H20
Now, there are a total of 13 oxygen atoms on the right and 2 at the left. To balance it, put 13/2 in front of O2
as shown below
C4H10 + 13/2O2 —> 4CO2 + 5H20
Now we multiply through by 2 clear off the fraction and we obtained:
2C4H10 + 13O2 —> 8CO2 + 10H20
We can divide this problem into 4 steps:
Step 1: Calculate mass of one liter solution from the density
Mass of solution = 1000 ml soln x
=1005 g soln
Step 2: Calculate the mass of acetic acid
Mass of CH₃COOH = 1005 g soln x (5.2 g / 100 g soln) = 52.26 g acetic acid
Step 3: Calculate the moles of acetic acid:
52.26 g acetic x (1 mole acetic / 60 g acetic) = 0.871 mol
step 4: Calculate the molarity of acetic acid:
molarity = moles of acetic / liters of soln = 0.871 / 1 L = 0.871 mole / L