Hey there!:
Concentration of NaOH = 0.200 M
Concentration of HNO₃= 0.200 M
Total volume = 50.0 mL + 60.0 mL = 110 mL=> 0.11 L
The neutralization reaction between NaOH and HNO3 :
OH⁻ + H⁺ ----------> H₂O
So :
n ( H⁺ ) = 60 mL * 0.200 M / 1000 mL => 0.012 moles of H⁺
n ( OH⁻ ) = 50 mL 0.200 M / 1000 mL => 0.01 moles of OH⁻
Hence OH⁻ is limiting reagent .
Remaining moles of H⁺ = 0.012 - 0.01 => 0.002 moles
Concentration of H⁺ = 0.002 M / 0.11 L
Concentration of H⁺ = 0.01818 moles/L
Therefore:
pH = - log [ H⁺ ]
pH = - log [ 0.01818 ]
pH = 1.74
Hope that helps!
Answer:
Q = 31798.4J = 31.79kJ
Explanation:
Heat energy (Q) = ?
Mass (m) = 152g
T1 = 24°C
T2 = 74°C
Specific heat capacity of water (c) = 4.184J/g°C
Q = Mc∇T
Q = 152 * 4.184 * (74 - 24)
Q = 635.968 * 50
Q = 31798.4J
Q = 31.79kJ
Heat required is 31.79kJ
The characteristic being calculated here is the mean or the average of the data set.
To check:
(20.73 + 20.76 + 20.68 + 20.75)/4 [we divide it by 4 because there are 4 numbers]
= 82.92 / 4
= 20.73
Answer: I think it is noble gasses.
Explanation: Use the website Dynamic Periodic Table for stuff like that it helps.
B is the answer I think hope this helps
