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Papessa [141]
3 years ago
13

Give an example of homeostasis in your body

Chemistry
1 answer:
Vinil7 [7]3 years ago
3 0
Answer:

So, basically Homeostasis is regulation and the. one seen almost every day is shivering or sweating. Our body's normal temperature is approximately 37° C and if you drop below that your body will regulate that by shivering or if you go above it you'll start to sweat to cool off you body and decrease your body temperature back to "equilibrium" or normal temp.
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if the theoretical yield of a reaction is 26.0 grams and you actually recovered 22.0 grams what is the precent yield
netineya [11]
Percentage Yield = (Actual Yield ÷ Theoretical Yield) × 100  

∴ if theoretical yield is 26 g, but only 22.0 is recovered from the reaction, 
then Percentage Yield = (22 g ÷ 26 g) × 100  
                                       =  84.6 %
8 0
3 years ago
Plz help me
AlekseyPX
All of the above would be the answer


mark me brainliest
8 0
2 years ago
Read 2 more answers
According to the principle of superposition, which statement is true about the sediment layers shown here?Required to answer. Si
podryga [215]

if layer 4 is at the very bottom it would be c

3 0
2 years ago
Which of the following is true for compounds?
Anuta_ua [19.1K]
What are the following?
6 0
3 years ago
A gas mixture is made up of kr (21.7 g), o2 (7.18 g), and co2 (14.8 g). the mixture has a volume of 23.1 l at 59 °c. calculate t
Scilla [17]

Answer:- partial pressure of Kr = 0.306 atm, partial pressure of oxygen = 0.264 atm and partial pressure of carbon dioxide = 0.396 atm

Total pressure is 0.966 atm

Solution:- moles of Kr = 21.7 g x (1mol/83.8g) = 0.259 mol

moles of oxygen = 7.18 g x (1mol/32g) = 0.224 mol

moles of carbon dioxide = 14.8 g x (1mol/44g) = 0.336 mol

Volume of container = 23.1 L and the temperature is 59 + 273 = 332 K

From ideal gas law equation, P = nRT/V

partial pressure of Kr = (0.259 x 0.0821 x 332).23.1 = 0.306 atm

partial pressure of oxygen = (0.224 x 0.0821 x 332)/23.1 = 0.264 atm

partial pressure of carbon dioxide = (0.336 x 0.0821 x 332)/23.1 = 0.396 atm

Total pressure of the gas mixture = 0.306 atm + 0.264 atm + 0.396 atm = 0.966 atm

4 0
3 years ago
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