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Iteru [2.4K]
2 years ago
5

Marc is 32 and married to Estella, who is 30. Estella is a stay-at-home mom to their two children, ages 1 and 4. They currently

live on Marc's salary of $110,000 (after taxes) that just about meets their household expenses. They would like to make sure that if Marc dies, they replace his income for 17 years, which would match their mortgage maturity and their kids would be well off to college; fund the children's college education ($300,000); establish a retirement fund for Estella ($250,000) to supplement Marc's Social Security retirement benefits; cover funeral costs ($10,000); and establish a 3-month emergency fund. If Estella dies, they want to have enough insurance to be able to pay for child care ($36,000 per year) and housekeeping services ($12,000 per year) for 17 years, to establish an emergency fund, and for funeral costs. They have the following financials:
Marc's employer provides a year's salary life insurance. Family is eligible for Social Security survivor benefits of $55,000 if Marc dies. Household expenses would be 20% lower if either parent dies. Current savings and investments of $23,000.
Using the financial needs approach, how much life insurance would you recommend?
A. $905,500 on Marc; $778,500 on Estella
B. $1,015,500 on Marc; $756,500 on Estella
C. $487,500 on Marc; $340,500 on Estella
D. $1,063,500 on Marc; $708,500 on Estella
Business
1 answer:
astraxan [27]2 years ago
6 0

Answer:

B. $1,015,500 on Marc ; $756,500 for Estella

Explanation:

Marc has current salary of $110,000 with which he runs the household expenses. If Marc dies then there should be more insurance coverage because he is the only person who earns in the house. Estella is a house wife and insurance coverage for her is lower than Marc because he will still be able to continue his earning.

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An automated assembly robot that cost $400,000 has a depreciable life of 5 years with a $100,000 salvage value. The MACRS deprec
OLga [1]

Answer:

book value at the end of year 3 = $115,200

Explanation:

\left[\begin{array}{ccccc}$Year&$Beginning&$Dep-Expense&$Acc. \: Dep&$Ending\\0&-&-&-&400,000\\1&400,000&80,000&80,000&320,000\\2&320,000&128,000&208,000&192,000\\3&192,000&76,800&284,800&115,200\\\end{array}\right]

Year 1 Depreciation expense

400,000 x 20% = 80,000

Year 2 Depreciation expense

400,000 x 32% =128,000

Year 3 Depreciation expense

400,000 x 19.2% = 76,800

Book value = carrying value - depreciation for the year

or

purchase - accumulated depreciation

3 0
2 years ago
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Andreas93 [3]

Answer:

the budgeted selling and administrative expenses for July is $64,100

Explanation:

The computation of the budgeted selling and administrative expenses for July is shown below:

= Budgeted selling & admin cost + (per unit sold × July units)

= $20,000 + ($9 × 4,900 units)

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hence, the budgeted selling and administrative expenses for July is $64,100

We simply applied the above formula

3 0
2 years ago
Shelby Corporation was organized in January to operate an air-conditioning sales and service business The charter issued by the
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Answer: Please refer to Explanation

Explanation:

This is how the stockholders' equity section of the balance sheet at December 31 should look like,

STOCKHOLDERS'S EQUITY

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If you need any clarification do comment.

8 0
2 years ago
Which of the following is NOT one of the three big categories for periodic evaluations:
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The category that does not belong to the periodic evaluation is Change Analysis.

Option D is the correct answer.

<h3>What is a periodic evaluation?</h3>

Periodic evaluation is a technique that is totally developmental in nature and disregards the formal advice relating to tenure, retention, or promotion of employees.

Periodic evaluation has three broad categories namely, hazard analysis, safety, and health-related inspections, and evaluation relating to personal protective equipment (PPE).

Therefore, out of the provided options, Change analysis is not considered a category for periodic evaluation.

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brainly.com/question/17095233

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4 0
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Solve for t using Google calculator
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6 0
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