Answer:
Well, carbon monoxide can be created from formic acid by adding sulphuric acid which will dehydrate said formic acid:
HCOOH
−
→
−
−
−
H
2
SO
4
CO+H
2
O
HCOOH→HX2SOX4CO+HX2O
Therefore, we can imagine the reverse reaction theoretically, which would make carbon monoxide an acidic oxide. However, the forward reaction does not proceed easily and it needs both the high acidity of sulphuric acid and its strong dehydrative properties to actually work. And your question mentions using hot, concentrated sodium hydroxide to make the reverse one work.
Most oxides that are classified as acidic or basic either have a very electrophilic central atom (e.g.
CO
2
COX2
) which can be attacked by the weak nucleophile water (which in turn can then release an acidic proton), or they have a high charge density on the oxygen which allows it to abstract a proton from water directly. Carbon monoxide is neither. If you check out its molecular orbitals, you will notice that even though carbon is partially positive it has the largest HOMO contribution, meaning a proton would be more likely to attatch to the carbon side — which doesn’t want one at all. The LUMO is, luckily, also more carbon-centred, meaning nucleophilic attacks on carbon are possible. However, it is also degenerate due to the double bond so that an attack is not favoured.
Thus, the carbon monoxide molecule is one that won’t react with water at all and totally defies the concept of acidic/basic oxides.
Abbreviations:
HOMO is a widely used abbreviation for the Highest Occupied Molecular Orbital, i.e. the one with the highest energy that still contains electrons. It is usually the orbital that will attack nucleophilicly or that will be attacked electrophilicly.
LUMO is a widely used abbreviation for the Lowest Unoccupied Molecular Orbital, i.e. the virtual (unoccupied) orbital that has the lowest energy. When considering a nucleophilic attack, the attacking electrons will usually interact with the LUMO. Electrophiles attack with other molecules’ HOMO with their LUMO.
Explanation:
Answer:
a.) Independent Variable: # of candy bars promised to each group
[ The Independent Varaiable is what you change in the experiment]
b.) Dependent Variable: Quiz Scores
[ The Dependent Variable is what you're testing in the experiment; what the experiment should affect]
c.) Constant(s): Same Quiz, same number of gender kids in each group, same age kids in each group, same ability, and same background. [and same time, I'm assuming.]
[Constants are what you keep the same in the experiment; what you're not changing.]
d.) Testable Question: Will promising kids candy make them do better on tests and quizzes? [or something along this lines of this]
[The Testable Question is what you're trying to find out in the experiment]
e.) Hypothesis: The more candy the students were promised, the better results Mrs. DeFord would get from them.
[The Hypothesis is what the person performing the experiment expects will happen; an educated guess]
f. Formal Conclusion: Data shows that kids who were promised more candy had a better average than kids who were promised less candy/none. Mrs. DeFord's hypothesis was correct, since she assumed the more candy the students were promised, the better they would do on the quiz.
[The Formal Conclusion is what you have learned from the experiment, and wether or not the hypothesis was correct or not.]
I hope this helps! :)
Answer:
Pure Water.
Explanation:
Solutions with a pH of 1-6 are considered acidic. Solutions with a pH of 8-14 are considered basic. Solutions with a pH of 7 are considered neutral.
1) list givens and convert if necessary
C₁ = 3.50 mol/L
V₁ = 0.550 L
C₂ = ?
V₂ = 0.275 L
2) rearrange formula
3) solve
C₂ = 7.00 mol/L
